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Reil [10]
2 years ago
13

Nevaeh is going to drive from her house to City A without stopping. Let DD represent Nevaeh's distance from City A tt hours afte

r leaving her house. The table below has select values showing the linear relationship between tt and D.D. Determine the distance from Nevaeh's house to City A, in miles.
t d
1 195
2 130
2.5 97.5
Mathematics
1 answer:
Zolol [24]2 years ago
7 0

Answer:

Step-by-step explanation:

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Someone help please i don’t want to fail math
VladimirAG [237]

Answer:

Image below!

Step-by-step explanation:

<u>Plotting </u>\underline{y=2x+3}<u />

Step 1: determine the y-intercept

(0,3)

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Step 2: Move 2 units up, and 1 unit left (keep repeating this process until you have reached the limit of the graph)

Step 3: Go to the other side of the graph of the first point (y-intercept)

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<em>When you've completed this process, it should look like this:</em>

5 0
2 years ago
Haley has five times as many stuffed animals as she does dolls. Her brother has 18 more video games than Haley has stuffed anima
34kurt

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Item 12
kozerog [31]

Answer:

The height is 4.472

Step-by-step explanation:

That formula is Heron's formula.

Where "s" is calculated like this:

s = (a + b + c) / 2

In this case:

a = 14

b = 12

c = 6

replacing:

s = (14 + 12 + 6) / 2

s = 16

Now we calculate the area:

A ^ 2 = 16 * (16−14) * (16−12) * (16−6)

A ^ 2 = 1280

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The area of the triangle is:

A = b * h / 2

In this case we will take the base as the longest side of the triangle, that is to say = 14

Thus:

h = A * 2 / b

h = 35.777 * 2/16

h = 4.472

So the height is 4.472

4 0
3 years ago
Oliwia made a scaled copy of the following triangle. She used a scale factor greater than 111. What could be the height of the s
GaryK [48]

Answer:

c,d,e

Step-by-step explanation:

6 0
2 years ago
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Simplify the expression. <br> (m^2n^-5)/m^7n^-17
guapka [62]

\dfrac{m^2n^{-5}}{m^7n^{-17}}=m^{2-7}n^{-5-(-17)}=m^{-5}n^{-5+17}=m^{-5}n^{12}\\\\=\dfrac{n^{12}}{m^5}\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}

4 0
3 years ago
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