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Debora [2.8K]
2 years ago
14

The equation p=1.5r graphed find price p, in dollars for r pounds of rice

Mathematics
1 answer:
disa [49]2 years ago
3 0

Answer:

Hope that help you mark me brinilylist

Step-by-step explanation:

Given that 5 pounds of rice at a store cost $6.50.

Then 1 pound of rice at a store cost = $6.50/5= $1.3

So the equation for the cost can be written as:

C=1.3P just like we write equation y=mx

Now we have to graph the cost C, vs pounds of rice.

Variable for Pounds of rice is not given so let it be "P"

So let's make a table for the number of pounds (P) and cost (C)  we can graph the points from that table to get the final graph.

The Attached graph is the final graph.

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Answer:

The answer will be 1/9

Step-by-step explanation:

any non zero expression will always be 1. you now have evaluate the powe (-3)^2 which will be 9. Answer should be 1/9. Good Luck!

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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
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Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

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The length and breadth of a rectangular field are 312m and 186m respectively; correct to the nearest metres. Between what limits
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Answer:

P \geq 1000 \; meters

Step-by-step explanation:

<u>Given the following data;</u>

Length = 312 meters

Breadth = 186 meters

To find the perimeter of the rectangle;

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To the nearest meters, we have;

Perimeter = 996 ≈ 1000 meters

Let P represent the perimeter of a rectangular field.

900 < P > 1000

Therefore, P \geq 1000 \; meters

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