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Firdavs [7]
3 years ago
8

Can I have help on this one

Mathematics
1 answer:
GaryK [48]3 years ago
4 0

Answer:

4. 40°

5.  15

6.

I hope this helps. I don't know the last one.

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What is 18 though 21?
Stells [14]
18. -500 + 250 = -250
19. -550 - 300 = - 850
20. 116 - (-50) = 116 + 50 = 166
21. 2500 + 1800 - 2200 = 2100
3 0
3 years ago
In the following expression, which of the following are like terms? 3m + 2n + 4m + 4
KatRina [158]
3m and 4m

Since 3m and 4m are attached to the same variable, they are like terms, since they can appropriately be combined.
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3 years ago
Jacobs & Johnson, an accounting firm, employs 15 accountants, of whom 9 are CPAs. If a delegation of 4 accountants is random
Artemon [7]
1st acc = 6/14 chance 
<span>2nd acc = 5/13 </span>
<span>3rd acc = 4/12 </span>

<span>6/14 * 5/13 * 4/12 = 0.0549450549 </span>

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7 0
3 years ago
What is the answer to x/3-2=7
Firlakuza [10]
<span> x/3-2=7
---------------------
SImplify
1/3x - 2 = 7
--------------------------
add 2 to each side
1/3x - </span><span><span>2 </span>+ 2 </span>= <span>7 + <span>2
1/3x = 9
------------------------------
Multiply each side by 3
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3 0
3 years ago
Which expressions are equivalent to \dfrac{4^{-3}}{4^{-1}} 4 −1 4 −3 ​ start fraction, 4, start superscript, minus, 3, end super
Slav-nsk [51]

Answer:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}

\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}

Step-by-step explanation:

Given

\dfrac{4^{-3}}{4^{-1}}

Required

Choose equivalent expressions

Choosing the first answer:

\dfrac{4^{-3}}{4^{-1}}

Split expressions

4^{-3} * \frac{1}{4^{-1}}

Apply laws of indices: (a^{-b} = \frac{1}{a^b})

\frac{1}{4^3} * \frac{1}{4^{-1}}

Apply laws of indices: (a^{-b} = \frac{1}{a^b})

\frac{1}{4^3} * \frac{1}{1/4}

\frac{1}{4^3} * \frac{4^1}{1}

\frac{4^1}{4^3}

Hence:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}

Choosing the second:

\dfrac{4^{-3}}{4^{-1}}

Apply law of indices: (\frac{a^m}{a^n} = a^{m-n})

So,

\dfrac{4^{-3}}{4^{-1}} = 4^{-3-(-1)}

\dfrac{4^{-3}}{4^{-1}} = 4^{-3+1)}

\dfrac{4^{-3}}{4^{-1}} = 4^{-2}

Apply law of indices: (a^{-b} = \frac{1}{a^b})

So:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}

4 0
3 years ago
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