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2 years ago

Please please help please

Mathematics

2 answers:

Readme [11.4K]2 years ago

7 0

Step-by-step explanation:

its .86 which is closer to .87

so choose the first one

viktelen [127]2 years ago

6 0

A 87 cuz i did the test

Step-by-step explanation:

I8 3menhj

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A flagpole is 10 feet tall. It’s shadow is 12 feet long how far is it from the top of the flagpole to the end of its shadow?

Genrish500 [490]

Answer:

The shadow is 11 Ft. away from the pole base.

Step-by-step explanation:

I just usually do this trick in situations like these where if x equals 1, and y equals 2, then z is gonna be 3. 2 goes after 1, and 3 goes after 2. This trick can work in other counting-up situations like this, as long as the number go up, and are right next to each other.

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Step-by-step explanation:

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2 years ago

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4(x-6)<-2x+6 what is the solution to the inequality _

Cloud [144]

Simplify both sides if needed. The left-hand side needs simplification.

4(x - 6) $\leq$ -2x + 6
4x - 24 $\leq$ -2x + 6

All is left to do is add and subtract to get the x variable all alone.

4x - 24 $\leq$ -2x + 6
6x - 24 $\leq$ 6 <-- Add 2x to both sides
6x $\leq$ 30 <-- Add 24 to both sides
x $\leq$ 5 <-- Divide both sides by 6

In order to be in the solution set, x has to be less than or equal to 5.

In interval notation: [5, -∞)

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2 years ago

A) -8 B) 0 C) 1 o/ 2 1 over 2 D) 8

seropon [69]

Your answer is C If not A have a good day

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2 years ago

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hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

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10 months ago