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madam [21]
3 years ago
15

In​ 2005, there were 14,100 students at college​ A, with a projected enrollment increase of 1000 students per year. In the same​

year, there were 34,350 students at college​ B, with a projected enrollment decline of 1250 students per year. According to these​ projections, when will the colleges have the same​ enrollment? What will be the enrollment in each college at that​ time?
Mathematics
1 answer:
Ede4ka [16]3 years ago
4 0

Let A be college A and let B be College B

A= 14,100

Rule: 1 Year = +1,000 students

B= 34,350

Rule: -1250 per year

1st Answer: 2017

Notice: I didn't show the formula because I'm not %100 sure I'm kind of off so if this is incorrect I'm deeply sorry. I truly am. On the bright side, I think its correct.

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nekit [7.7K]

Answer:68.3 degrees

Step-by-step explanation:

The diagram of the triangle ABC is shown in the attached photo. We would determine the length of side AB. It is equal to a. We would apply the cosine rule which is expressed as follows

c^2 = a^2 + b^2 - 2abCos C

Looking at the triangle,

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a = 80 miles.

Angle ACB = 180 - 42 = 138 degrees. Therefore

c^2 = 80^2 + 75^2 - 2 × 80 × 75Cos 138

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c^2 = 6400 + 5625 - 12000 × -0.7431

c^2 = 12025 + 8917.2

c = √20942.2 = 144.7

To determine A, we will apply sine rule

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80/SinA = 144.7/Sin 138

80Sin 138 = 144.7 SinA

SinA = 53.528/144.7 = 0.3699

A = 21.7 degrees

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8 0
3 years ago
Taylor walks 7 miles in 2 hours. At what unite rate dose Taylor walk
IRISSAK [1]

Answer:

C

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6 0
2 years ago
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Step-by-step explanation:

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8 0
2 years ago
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