Answer:
3 2 /5 ×3
change 3 2 /5 into an improper fraction
then you will get 17 /5
after that you say 17/5 ×3/1
=(17×3)/ (5x1)
=51/5 (51÷5)
=10.2/ 10 1/5
How to solve your problem
Topics: Algebra, Quadratic Equation
2
+
1
=
−
3
2x+1=x-3
2x+1=x−3
Solve
1
Subtract
1
1
1
from both sides of the equation
2
+
1
=
−
3
2x+1=x-3
2x+1=x−3
2
+
1
−
1
=
−
3
−
1
2x+1{\color{#c92786}{-1}}=x-3{\color{#c92786}{-1}}
2x+1−1=x−3−1
2
Simplify
Subtract the numbers
Subtract the numbers
2
=
−
4
2x=x-4
2x=x−4
3
Subtract
x
x
from both sides of the equation
2
=
−
4
2x=x-4
2x=x−4
2
−
=
−
4
−
2x{\color{#c92786}{-x}}=x-4{\color{#c92786}{-x}}
2x−x=x−4−x
4
Simplify
Combine like terms
Multiply by 1
Combine like terms
=
−
4
x=-4
x=−4
Solution
=
−
4
Answer:
y>-2
Step-by-step explanation:
Answer on E2020
Answer:
a) 
b) 0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:

The probability of finding a value between c and d is:

The probability of finding a value above x is:

The probability density function of the uniform distribution is:

The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.
This means that
.
a. Give a mathematical expression for the probability density function of driving distance.

b. What is the probability the driving distance for one of these golfers is less than 290 yards?

0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
<em />
As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,