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Marizza181 [45]
3 years ago
12

Pass a brotha some help :(

Mathematics
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer and Step-by-step explanation:

Distribute the 1p to the y and -6 and distribute the 2 to the 3y and 6.

10y - 50 + 6y + 12

Now, combine like terms.

16y - 38

#teamtrees #PAW (Plant and Water)

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ANSWER CORRECT FOR BRAINLIEST
monitta

Answer:

3 2 /5 ×3

change 3 2 /5 into an improper fraction

then you will get 17 /5

after that you say 17/5 ×3/1

=(17×3)/ (5x1)

=51/5 (51÷5)

=10.2/ 10 1/5

3 0
2 years ago
Read 2 more answers
Solve the equation 2x+1=x-3​
Agata [3.3K]

How to solve your problem

Topics: Algebra, Quadratic Equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

Solve

1

Subtract

1

1

1

from both sides of the equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

2

+

1

−

1

=

−

3

−

1

2x+1{\color{#c92786}{-1}}=x-3{\color{#c92786}{-1}}

2x+1−1=x−3−1

2

Simplify

Subtract the numbers

Subtract the numbers

2

=

−

4

2x=x-4

2x=x−4

3

Subtract

x

x

from both sides of the equation

2

=

−

4

2x=x-4

2x=x−4

2

−

=

−

4

−

2x{\color{#c92786}{-x}}=x-4{\color{#c92786}{-x}}

2x−x=x−4−x

4

Simplify

Combine like terms

Multiply by 1

Combine like terms

=

−

4

x=-4

x=−4

Solution

=

−

4

5 0
3 years ago
Given f(x) = ex and g(x) = x -2, what is the range of (gºf)(x)? ​
lesya [120]

Answer:

y>-2

Step-by-step explanation:

Answer on E2020

7 0
2 years ago
Read 2 more answers
The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards (according to GolfWeek). Assume th
Usimov [2.4K]

Answer:

a) f(x) = \frac{1}{25.9}

b) 0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

The probability density function of the uniform distribution is:

f(x) = \frac{1}{b-a}

The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.

This means that a = 284.7, b = 310.6.

a. Give a mathematical expression for the probability density function of driving distance.

f(x) = \frac{1}{b-a} = \frac{1}{310.6-284.7} = \frac{1}{25.9}

b. What is the probability the driving distance for one of these golfers is less than 290 yards?

P(X < 290) = \frac{290 - 284.7}{310.6-284.7} = 0.2046

0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

3 0
2 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
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