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tatiyna
4 years ago
9

As a maintenance electrician, it takes you 40 minutes to rewire a motor. You have 6 motors to rewire.

Mathematics
1 answer:
bazaltina [42]4 years ago
7 0

Answer:

The maintenance electrician takes 287.555555566667 hours to to rewire all the motors

Step-by-step explanation:

1. Calculate all of the minutes for all the numbers.

It takes you 26.6666667 minutes to rewire 2/3 of a motor.

It takes you 160 minutes to rewire 4 motors.

It takes you 266.666667 to rewire 6 2/3 motors

It takes you 7,200 minutes to rewire 180 motors

It takes you 9,600 minutes to rewire 240 motors

2. Add all of the minutes together.

26.666667 + 160 + 266.666667 + 7,200 + 9,600 = 17253.333334

It takes you 17253.333334 minutes to rewire 431.333333 motors

3. Convert minutes to hours

17253.333334/60 = 287.555555566667

It takes you 287.555555566667 hours to rewire all the motors

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75 pts if you can awnser this
stellarik [79]

Answer:

x = 4

Step-by-step explanation:

2.5x +6 = 3.25x +3

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6 = 0.75x +3

-3              -3

3 = 0.75x

divide by 0.75 both sides

4 = x

or

x = 4

7 0
3 years ago
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Ostrovityanka [42]

Answer:

Yes it's parallel

Step-by-step explanation:

Lines with the same slope are parallel.

The slope is -2.

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The ___ is the part of the neuron that carries information away from the cell body.
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axons

Step-by-step explanation:

The axons  is the part of the neuron that carries information away from the cell body.

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The sum of three consecutive terms in an arithmetic sequence is 27, and their product is 585. find the three terms.
sammy [17]
\text{the three consecutive terms in an arithmetic sequence}\\a;\ a+d;\ a+2d\\\\\text{system of equals}\\\\ \left\{\begin{array}{ccc}a+a+d+a+2d=27\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}3a+3d=27&|:3\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}a+d=9&\to d=9-a\\a(a+d)(a+2d)=585\end{array}\right\\
\text{substitute to the second equation}\\\\a(a+9-a)(a+2(9-a))=585\\\\a(9)(a+18-2a)=585\\9a(18-a)=585\ \ \ |:9\\a(18-a)=65\\18a-a^2=65\ \ \ |\text{change the signs}\\a^2-18a=-65\\a^2-2a\cdot9=-65\ \ \ |+9^2\\\underbrace{a^2-2a\cdot9+9^2}_{(a-b)^2=a^2-2ab+b^2}=-65+9^2\\(a-9)^2=16\to a-9\pm\sqrt{16}\\a-9=-4\ \vee\ a-9=4\ \ \ |+9\\a=5\ \vee\ a=13\\\\d=9-5=4\ \vee\ d=9-13=-4
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5 0
3 years ago
7.) Solve the system of equations<br> below. <br> -2x + 3y = 9 2/3x + 2y = 0
iren [92.7K]

Answer:

So lets isolate y

we have

-2x+3y=9

2/3x +2y=0

Im gonna do the first equation

so -2x + 3y = 9

Add 2x on both sides

3y= 9+ 2x

Now divide by 3 to isolate y

y= 3+ 2/3x

Now we can subsitute y into any eqaution (I’m gonna do the second one) to solve.

2/3x+ 2(3+ 2/3x)= 0

Solve:

2/3x+ 6 + 4/3x = 0

6/3x +6= 0

2x+6=0

2x= -4

x= -2

Now we can subsitute this for any equation.

so I’m gonna do the first equation

-2(-2)+3y=9

4+3y=9

3y= 5

y= 5/3

y= 1 2/3

Final answer:

x=-2

y= 1 2/3

6 0
2 years ago
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