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2 years ago

Plssss help me i don’t understand

Mathematics

2 answers:

Svetlanka [38]2 years ago

6 0

Answer:

suppose that is the answer

Yanka [14]2 years ago

4 0

What she said above is an example to that question

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Can someone PLEASE answer the Algebra Question CORRECTLY BELOW!

Maru [420]

From The picture 2 barrels = 73 gallons

Divide by 2 for gallons per barrel:

73/2 = 36.5 gallons per barrel

Multiply gallons per barrel barrels:

36.5 x 0.045 = 1.6425 gallons.

Rounded to 2 decimals = 1.64

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2 years ago

SOMEONE PLEASE PLEASE HELP I NEED THE ANSWERS YO BOTH PF THESE PLEASE

ella [17]

Answer:

1. c; 2. d

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1. 2*3 = 6

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2 years ago

Compute the sum of all nine 2-digit numbers with a ones digit of 6.

serg [7]

Answer: 504

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

Estimate how many times larger 4 x 10^15 is than 19 x 10^12.

chubhunter [2.5K]

Whats the answer

i am working on the same test right now

4 0

3 years ago