On the 40th and the 80th you will receive both a free beverage and a free appetizer. You can find this by simply finding the multiples of both number up to 100 (or a little more than 100) to find out on which dates you'd get bothe an appetizer and beverage for free. Here are the multiples of both, to prove this answer.
- 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104.
- 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100.
Thus making 40 and 80 the answers. I hope this helps!
Answer:
-2x + 6 
8x or 5x + 3 < 9
Step-by-step explanation:
-2x + 6 8x -> x
3/5
5x + 3 < 9 -> x < 6/5
D = 545.79
r = 48.3
Plug in numbers to corresponding variables
545.79 = t(48.3)
Isolate the t, divide 48.3 from both sides
(545.79)/48.3 = 48.3t/48.3
t = 545.79/48.3
t = 11.3
t = A) 11.3 h
hope this helps
Multiply is product. Divide is quotient
Answer:
128 men
Step-by-step explanation:
90 × 28 × 8 = M × 18 × 15/2
M = 128
