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3 years ago

Doug's Gross Monthly Earnings is $4000. Calculate his net pay (take-home pay) by using the deductions below.

Mathematics

1 answer:

Butoxors [25]3 years ago

7 0

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<h3>= 12% + 3% + 1% + 6% + 6%</h3><h3>= 28%</h3><h3>= 28% × $4,000 ÷ 100</h3><h3>= $1,120</h3><h3>= $4,000 - $1,120</h3><h3>= <u>$2,880</u></h3><h3>Doug's Net Salary Is $2,880</h3>

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With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the en

mrs_skeptik [129]

Answer:

0.9167 = 91.67% probability that the entire batch will be accepted

Step-by-step explanation:

The CDs are chosen without replacement, which means that the hypergeometric distribution is used.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

2100 write-rewrite CDs, and 60 are defective.

This means, respectively, that $N = 2100, k = 60$

3 of these CDs are randomly selected for testing

This means that $n = 3$

What is the probability that the entire batch will be accepted?

Probability of none defective, so P(X = 0).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,2100,3,60) = \frac{C_{60,0}*C_{2040,3}}{C_{2100,3}} = 0.9167$

0.9167 = 91.67% probability that the entire batch will be accepted

5 0

3 years ago

Solve <br><br> 4a - b^2 <br><br> a = 3<br> b = 2<br> c = 1

Nastasia [14]

Answer:

Step-by-step explanation:

(4)(3)−22

3 0

3 years ago

What value is a discontinuity of x squared plus 5 x plus 2, all over x squared plus 2 x minus 35?

iVinArrow [24]

The value of discontinuity is x= -7, x= 5

6 0

3 years ago

Read 2 more answers

Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv

Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = $\dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}$

Let dD/dT = 0 to find the critical value we will get

$\dfrac{70000000\left(291T^2-24298T+91800\right)}$ = 0

Using formula of quadratic, we get the roots:

T = 79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

$-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}$

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8) a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

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3 years ago

HELP NEED ASAP!!!!!!

Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

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3 years ago