To determine the minimum of an equation, we derive the <span>equation using differential calculus twice (or simply </span><span>take the second derivative of the function). If the </span><span>second derivative is greater than 0, then it is minimum; </span><span>else, if it is less than 1, the function contains the </span><span>maximum. If the second derivative is zero, then the </span><span>inflection point </span><span>is</span><span> identified.</span>
Answer:
z=( -2 , 5/3) can you speak English
We are going to need to know the formula for the lateral surface area and volume of a cylinder in order to find our answers. Below are the equations:
is the height
is the radius
Using these formulas, we can solve these problems.
Ok so to find which sides are congruent we need to know their lengths.
To find the length we need the distance formula between two point ->
√(X2-X1)∧2 +(Y2-Y1)∧2
Ok lets find the first side PQ
P(-1,3) Q(2,-1)
X1 Y1 X2 Y2
√(2-(-1)∧2 + (-1-3)∧2 = 5
Now PR
P (-1,3) R (5,3)
X1 Y1 X2 Y2
√(5-(-1))∧2 + (3-3)∧2) = 6
Now the last side QR
Q (2, -1) R (5,3)
X1 Y1 X2 Y2
√(5-2)∧2 + (3-(-1))∧2 = 5
From the above work we see that PQ and QR are congruent becuase they are equal PQ=QR
Also the opposite angles of these sides are congruent. Hope this helps :).
