Question

HELP ME HELP ME HELP ME!!! Given f(x) below, find f^-1(x).

Answer 1

Answer:

$f^{-1}$ (x) = 6 - 4x

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = - $\frac{1}{4}$ x + $\frac{3}{2}$ ( multiply through by 4 to clear the fractions )

4y = - x + 6 ( subtract 6 from both sides )

4y - 6 = - x ( multiply through by - 1 )

- 4y + 6 = x

Change y back into terms of x with x = $f^{-1}$ (x) , then

$f^{-1}$ (x) = 6 - 4x