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ikadub [295]
3 years ago
5

HELP ME HELP ME HELP ME!!! Given f(x) below, find f^-1(x).

Mathematics
1 answer:
elixir [45]3 years ago
7 0

Answer:

f^{-1} (x) = 6 - 4x

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = - \frac{1}{4} x + \frac{3}{2} ( multiply through by 4 to clear the fractions )

4y = - x + 6 ( subtract 6 from both sides )

4y - 6 = - x ( multiply through by - 1 )

- 4y + 6 = x

Change y back into terms of x with x = f^{-1} (x) , then

f^{-1} (x) = 6 - 4x

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Consider the equation 0.75⋅10^w/3=30
Nastasia [14]

Answer:

The value of w is:

w=3\cdot log_{10}(40)

Step-by-step explanation:

We have to calculate w from the equation

0.75\cdot 10^{w/3}=30

The solution has to be expressed as a logarithm in base 10.

We can solve it like:

0.75\cdot10^{w/3}=30\\\\10^{w/3}=30/0.75=40\\\\(w/3)log_{10}(10)=log_{10}(40)\\\\w/3=log_{10}(40)\\\\w=3\cdot log_{10}(40)

The value of w is:

w=3\cdot log_{10}(40)

5 0
3 years ago
In this particular arithmetic sequence, a7 = 34 and a15 = 74. What is the value of a21?
Karo-lina-s [1.5K]
So i believe its <span> a21 = 109 a21 = 85 a21 = 108 a21 = 104.

So the answer would be 104 

Hope this helps</span>
5 0
3 years ago
Help me solve these problems please
Romashka [77]
I hope it makes sense.

7 0
3 years ago
Suppose a casino invents a new game that you must pay $250 to play. The game works like this: The casino draws random numbers be
lubasha [3.4K]

Answer:

clc%clears screen

clear all%clears history

close all%closes all files

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M=[];

for i=1:100000

re=0;

S=0;

while(S<=1)

S=S+rand;

re=re+100;

end

M(i)=re;

end

disp('Expected received money is');

mean(M)

disp('Since expcted is greater than what we pay. So, we will play')

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP
shusha [124]
15 meals x $0.80 = $12.
$18 - $12 = $6.

If one movie ticket is $3 then she must have purchased 2 with $6.

Part A - 15x0.8=18-x=x

Part B-
15 x 0.8 = 12
18- 12=6

Part C- 2

6 0
3 years ago
Read 2 more answers
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