Answer:
double the bandwidth assigned per channel to 40 MHz
Explanation:
The best way of doing this would be to double the bandwidth assigned per channel to 40 MHz. This will make sure that the capacity is more than sufficient. This is simply because the bandwidth of a channel represents how much information can pass through the channel at any given second, the larger the channel, the more information/data that can pass at the same time. Therefore, if 20 MHz is enough for the network, then doubling this bandwidth channel size would be more than sufficient capacity for the network to handle all of the data.
I believe the answer would be true
Answer:
1, 4, 7
Explanation:
The instruction in the question can be represented as:
for i in range(1,10,3):
print i
What the above code does is that:
It starts printing the value of i from 1
Increment by 3
Then stop printing at 9 (i.e.. 10 - 1)
So: The sequence is as follows
Print 1
Add 3, to give 4
Print 4
Add 3, to give 7
Print 7
Add 3, to give 10 (10 > 10 - 1).
So, it stops execution.
Answer:
Preamble
Explanation:
In the computer network , the ether-net is the frame of link layer protocol data. This frame is used ether net with physical layer of transport mechanism. The ether net frame is of different type.
- The ether-net II
- The Novel raw IEEE 802.3
- IEEE 802.2 LLC
- IEEE 802.2 SNAP
Each of the Ethernet frame started from Ether net header. It contains the source and the destination. The MAC address is called its first two address.
Rand.int(your_num , your_num
