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VikaD [51]
3 years ago
8

Please simplify this! 14x - 4 - 2x - 3 = ​

Mathematics
2 answers:
Fittoniya [83]3 years ago
8 0

Answer:

12x-7=

Step-by-step explanation:

Just do -3 + -4 and 14x - 2x

Debora [2.8K]3 years ago
3 0

Answer:

12x - 7 <em>or </em>-7 + 12x <em>(changing the order of the values will not change the answer!)</em>

Step-by-step explanation:

identify the first set of like terms that you're going to combine. i'm going to start with the x terms. you don't have to start with those, but that's just how i'm going to do it.

<u>14x</u> - 4 <u>- 2x</u> - 3

combine the first set of like terms.

14x - 2x

after subtracting 2x, you're left with 12x.

identify the remaining like terms from the original expression.

14x <u>- 4</u> - 2x <u>- 3</u>

combine the remaining like terms.

-4 - 3 <em>aka -4 + -3</em>

after subtracting 3 from -4, you're left with -7.

i hope this helps! have a great day <3

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What should be subtracted from -8xy + 2x^2 + 3y^2 to get x^2 + 2
Minchanka [31]

Answer:

x^2 - 8xy + 3y^2 - 2

Step-by-step explanation:

(-8xy + 2x^2 + 3y^2) - unknown = x^2 + 2

- unknown = x^2 + 2 + 8xy - 2x^2 - 3y^2

- unknown = -x^2 + 8xy - 3y^2 + 2

Unknown = x^2 - 8xy + 3y^2 - 2

Check:

(-8xy + 2x^2 + 3y^2) - (x^2 - 8xy + 3y^2 - 2)

= -8xy + 2x^2 + 3y^2 - x^2 + 8xy - 3y^2 + 2

= -8xy + 8xy + 2x^2 - x^2 + 3y^2 - 3y^2 + 2

= x^2 + 2

8 0
3 years ago
What is 23/9 as a mixed number
Genrish500 [490]
2 5/9. Because you first find how many times 9 goes into 23 and then subtract the sum of it from the denominator and keep the same denominator as your answer.
3 0
3 years ago
What is 14r-13s+19r+13s-18
Zielflug [23.3K]
77 is ur answer hope this helps u
8 0
3 years ago
Which of the binomials below is a factor of this trinomial x^2+4x+4
dmitriy555 [2]
X² + 4x + 4
x            2
x             2

(x + 2) (x + 2) 


x + 2 should be your answer

binomial is having 2 terms

hope this helps
4 0
3 years ago
Read 2 more answers
Question 5: prove that it’s =0
mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that \cos(\frac{2}{x}) is a variable number between -1 and 1 (inclusive).

This means that -1 \le \cos(\frac{2}{x}) \le 1.

x^4 \ge 0 for all value x. So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

By squeeze theorem, if  -x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

and \lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L, then we can also conclude that \im_{x \rightarrow} x^4\cos(\frac{2}{x})=L.

So we can actually evaluate the "if" limits pretty easily since both are continuous  and exist at x=0.

\lim_{x \rightarrow 0}x^4=0^4=0

\lim_{x \rightarrow 0}-x^4=-0^4=-0=0.

We can finally conclude that \lim_{\rightarrow 0}x^4\cos(\frac{2}{x})=0 by squeeze theorem.

Some people call this sandwich theorem.

6 0
3 years ago
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