Put equal parts of each 12%+38%=50%
50% divided by 2= 25%
The perimeter is 40 cm. You would take the square root of 100 which is 10. 10 would be the length of each side since it is a square and all sides are equal.
✦ Explanation <span>✦
Find the unit rate by dividing the total amount of hours by the timing.
</span>
![\frac{18}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B18%7D%7B4%7D%20)
is the unit rate which can also be converted to
![4.5](https://tex.z-dn.net/?f=4.5)
or written as
![18:4](https://tex.z-dn.net/?f=18%3A4)
.
<span>Hope that helps! ★ If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia</span>
![\bf \begin{array}{llllll} \textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\ \textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\ y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x} \\ &&y=\cfrac{{{ k}}}{x} \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllllll%7D%0A%5Ctextit%7Bsomething%7D%26%26%5Ctextit%7Bvaries%20inversely%20to%7D%26%5Ctextit%7Bsomething%20else%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Ctextit%7Bsomething%7D%26%3D%26%5Ccfrac%7B%7B%7B%5Ctextit%7Bsome%20value%7D%7D%7D%7D%7B%7D%26%5Ccfrac%7B%7D%7B%5Ctextit%7Bsomething%20else%7D%7D%5C%5C%20%5Cquad%20%5C%5C%0Ay%26%3D%26%5Ccfrac%7B%7B%7B%5Ctextit%7Bk%7D%7D%7D%7D%7B%7D%26%5Ccfrac%7B%7D%7Bx%7D%0A%5C%5C%0A%26%26y%3D%5Ccfrac%7B%7B%7B%20%20k%7D%7D%7D%7Bx%7D%0A%5Cend%7Barray%7D)
with "k" being the "constant of variation"
so. hmm in this case is "w" inversely varying to the square of the distance or d²
thus
![\bf w=\cfrac{k}{d^2}\qquad \begin{cases} d=3978\\ w=129 \end{cases}\implies 129=\cfrac{k}{3978^2}](https://tex.z-dn.net/?f=%5Cbf%20w%3D%5Ccfrac%7Bk%7D%7Bd%5E2%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ad%3D3978%5C%5C%0Aw%3D129%0A%5Cend%7Bcases%7D%5Cimplies%20129%3D%5Ccfrac%7Bk%7D%7B3978%5E2%7D)
solve for "k", to see what the constant of variation is
and plug it back in
![\bf w=\cfrac{k}{d^2}](https://tex.z-dn.net/?f=%5Cbf%20w%3D%5Ccfrac%7Bk%7D%7Bd%5E2%7D)
now.. .to find her weight when she's 144miles above the surface, well
that's just
![\bf w=\cfrac{k}{(3978+144)^2}](https://tex.z-dn.net/?f=%5Cbf%20w%3D%5Ccfrac%7Bk%7D%7B%283978%2B144%29%5E2%7D)
and since you already know what "k" is, just divide and simplify away, to get "w"
For example:
L plus W
3 plus 6= 9
I plus W
4 plus 6= 10
total: 9+10= 19
(this is just an example)