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Verdich [7]
3 years ago
9

A large on folded flag has an area of 2048 cm^2 and is folded into fourths, and then fourths again, and so on. Record the area o

f a region of the flag after each fold.
Describe the pattern of change in the table and write an equation between the area of a region a and the number of folds n.
​

Mathematics
1 answer:
ratelena [41]3 years ago
3 0

Answer:

a = 2048 × (¼)^n

Step-by-step explanation:

Area after a fold is ¼th of the previous area

One fold: a = 2048 × ¼

Two folds: a = (2048 × ¼) × ¼

= 2048 × (¼)²

Three folds: a = (2048 × (¼)²) × ¼

= 2048 × (¼)³

a = 2048 × (¼)^n

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A bakery makes 40 different flavors of muffins. 25% of the flavors have chocolate as one of the ingredients. How many flavors ha
Likurg_2 [28]

Answer:

10

Step-by-step explanation:

because 25%of 40 is 10

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Which expression is equivalent to (- 2c / d^2)^3
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Answer:idk

Step-by-step explanation:

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3 years ago
A number, n, is multiplied by - 5/8. The products is - 0.40 What is the value of n? It would also help if you would explain how
Kay [80]
I'm not sure if those numbers are negatives or thats just a hyphen but:

N(-5/8)=-0.40

Division is always the opposite of multiplication

-0.40/(-5/8)=0.64

N=0.64
5 0
3 years ago
If y varies directly as x and x = 9 when y = 15 , find y when x = 33
poizon [28]
This would practically be very reliable of course. We can see in the sentence above that y and x, and x and y are both depending on each other. So, now that this has been considered, we can see that whenever "x" would be a certain number, this would show you that "y" would also be a certain number, and depending how much "x" or "y" would move, it would also change these variable no matter how they move.

This would be a matter of division. As we can see above on how 9 and 15 could be divisible down the line as they multiply.

Therefore, we would then see how many times would "x" which is 9, how many times that would go in 33.

Let's start!

\boxed{33\div9= \ (3.6)}

We take this "3.6" away from this, and we would plug it into "y".

We then do the following:

\boxed{3.6*15=55}

Therefore, when "x" = 33, "y" would then equal 55.

Your answer: \boxed{\boxed{\bf{y=55}}}
5 0
3 years ago
Read 2 more answers
Solve:
Natalija [7]
Answer: It took 18 Months for Michelle to collect 59 dolls.


Explanation:
First, let’s right an equation for this. Michelle started with 5 dolls in a bar collection (I have no clue what that is but i’ll roll with it), and each month she bought 3 more, so 5 dolls plus the 3 dolls per month equals 59 at some point.

5 dolls + 3 dolls per month = 59 dolls
OR
5 + 3m = 59

The point of this question is to find how many months (m) it took in order to get to 59 dolls and there’s multiple ways you can do this:

1) just plug in random numbers into m to see how long it takes to get to 59 [this option might take a while]

2) Try to isolate m (get every number out of the equation) to find out the value of m. [I’m most familiar with this way]

First, subtract 5 from 5 in the equation in order to get rid of it, since we’re trying to get all whole numbers out of the equation and only have m left. You subtract 5 from 59 since the equal sign is kind of like a mirrror, whatever you do to one side you have to do to the other. So, 5-5 is 0, and 59- is 54.

Now you’re left with 3m=54. In order to isolate the m, divide 3 by 3 to get rid of the 3, then divide 54 by 3, which is 18.

In order to check your work, plug 18 into m just to see if it works or not:

5+3m=59 —-> 5+ 3(18)= 59

3 times 18 is 54, plus 5 is 59. So, Mi hells took 18 months to collect her 59 dolls. Hope this helped!
3 0
3 years ago
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