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3 years ago

9

A large on folded flag has an area of 2048 cm^2 and is folded into fourths, and then fourths again, and so on. Record the area o

f a region of the flag after each fold.
Describe the pattern of change in the table and write an equation between the area of a region a and the number of folds n.

1 answer:

ratelena [41]3 years ago

3 0

Answer:

a = 2048 × (¼)^n

Step-by-step explanation:

Area after a fold is ¼th of the previous area

One fold: a = 2048 × ¼

Two folds: a = (2048 × ¼) × ¼

= 2048 × (¼)²

Three folds: a = (2048 × (¼)²) × ¼

= 2048 × (¼)³

a = 2048 × (¼)^n

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denis-greek [22]

Answer:

$\frac{7}{10} |$

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

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Complete the multiplication and the equation becomes

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The two fractions now have like denominators so you can add the numerators.

Then:

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This fraction cannot be reduced.

The fraction 41/30

is the same as

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Convert to a mixed number using

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41/30 = 1 11/30

Therefore:

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STEP 2:

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The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

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The two fractions now have like denominators so you can add the numerators.

Then:

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Therefore:

$\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}$ |

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Crank

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mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em> $h(t)$ <em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em> $h(t) = 3 +90\cdot t -16\cdot t^{2}$ <em>, where </em> $t$ <em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

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By Quadratic Formula:

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