Find the solution for the following equations using substitution or elimination:
1 answer:
Answer:
(4, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equation using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
2x - 3y = 5
4x + 2y = 18
<u>Step 2: Rewrite systems</u>
2x - 3y = 5
y = 9 - 2x
<u>Step 3: Solve for </u><em><u>x</u></em>
- Substitute: 2x - 3(9 - 2x) = 5
- Distribute -3: 2x - 27 + 6x = 5
- Combine like terms: 8x - 27 = 5
- Add 27 on both sides: 8x = 32
- Divide 8 on both sides: x = 4
<u>Step 4: Solve for </u><em><u>y</u></em>
- Define: 2x - 3y = 5
- Substitute: 2(4) - 3y = 5
- Multiply: 8 - 3y = 5
- Isolate <em>y</em> term: -3y = -3
- Isolate <em>y</em>: y = 1
And we have our final answer!
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Answer:
C, D
Step-by-step explanation:
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Answer:
3/10
Step-by-step explanation:
2/5 + x = 7/10
x = 7/10 - 2/5
x = 7/10 - 4/10
x = 3/10