Answer:
Step-by-step explanation:
According to the table, function g(x) reaches the max height of 33, approx.
The equation of motion is f(x) = -16x^2 + 42x + 12. We need to determine the maximum of this function. To do this, find the x-coordinate of the vertex, which is x = -b/(2a), or x = -42/(2*-16), or 1.31 sec.
Evaluating f(x) = -16x^2 + 42x + 12 at x = 1.31 sec, we get f(1.31) = 39.6.
So it appears that f(x) has a higher max than does g(x); the difference is approx. 39.6 - 33, or 6.6
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Answer:
Let S = starting point
Let ST = length of tunnel
SR = 1414 m
RT = 2236 m
Set up:
ST^2 + SR^2 = RT^2
ST^2 + (1414)^2 = (2236)
Solve for RT to find your answer.
Step-by-step explanation:
