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Delicious77 [7]
3 years ago
8

Quick answers please!!!!!! I literally have no idea

Mathematics
2 answers:
Yanka [14]3 years ago
5 0

Answer:

The solution to this question is 104.25cm²

Step-by-step explanation:

u

Triss [41]3 years ago
5 0

Answer:

hi

Step-by-step explanation:

i think so

A=

= \pi \times  {r}^{2}

=3,14×5,76²=104,177

hope it helps

have a nice day

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PLEAASE HELP DUE TODAY
Kryger [21]

Answer:

I'm not sure but try 13.5.

Step-by-step explanation:

It might not be correct sorry

8 0
3 years ago
3.An increasing linear function with independent variable x and dependent variable y approaches the point (−1, 1). If this funct
lakkis [162]

Answer:

3.

C. The domain is (1,+[infinity]) and the range is (-1,+[infinity])

4.

B. 6

5.

A. (-[infinity], 3)

Step-by-step explanation:

The Linear function has one independent and one dependent variable. The value of dependent variable can be found by taking the equation equals to 0. The domain function is set to analyse the range. The range can be set as -1 to 1. Any number between this is acceptable but outside this is not considered in the domain.

7 0
3 years ago
Alan needs to manufacture a circular metal plate with a perimeter of `10pi` centimeters. If the allowed error tolerance in the p
AnnZ [28]

The ideal radius Alan must control is \frac{1}{2\pi } cm.

<h3>Define perimeter of circle.</h3>

The measurement of the circle's perimeter, also known as its circumference, is called the circle's boundary. The area of a circle determines the space it takes up. A circle's diameter is equal to the length of a straight line traced through its center. Usually, it is stated in terms of units like cm or m.

Given data -

Perimeter of circular plate = 10\pi cm

We know that perimeter of a circle is 2\pir

Therefore   10\pi = 2\pir

r = 5 cm

The given error Alan can make is +-1 cm.

Minimum radius is given by

2\pir = 10\pi - 1

r = \frac{10\pi - 1 }{2\pi }

r = 5 - \frac{1}{2\pi }

Maximum radius is given by

2\pir = 10\pi + 1

r = \frac{10\pi + 1 }{2\pi }

r = 5 + \frac{1}{2\pi }

The ideal radius Alan must control is \frac{1}{2\pi } cm.

To know more about perimeter of circle, visit:

brainly.com/question/2718232

#SPJ1

5 0
2 years ago
) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp
Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

<em>Let </em>\bar X<em> = sample average salary</em>

The z-score probability distribution for sample mean is given by;

                 Z = \frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = mean salary = $1.5 million

            \sigma = standard deviation = $0.9 million

             n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P(\bar X > $1.1 million)

    P(\bar X > $1.1 million) = P( \frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} } >  \frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} } ) = P(Z > -8.89) = P(Z < 8.89)

<em>Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.</em>

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0
3 years ago
1.Find the area of a circle with the radius of 48mm
OLga [1]

Answer:

hope it helps you see the attachment for further information....

3 0
4 years ago
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