Answer:
Area of circle R = 75π un² or ≈235.5 un²
Step-by-step explanation:
The problem says that m∠TRS = 120º. The total number of degrees in a circle is 360º. 120º is a third of 360º. Therefore, we can prove that the shaded sector is a third of the circle.
The problem then says that the area of the shaded sector is 25π and we have to calculate the area of the entire circle. Since we already know that the shaded sector is a third of the circle, we can simply multiply 25π by 3 in order to calculate the area of t he entire circle.
25π × 3 = 75π.
Area of circle R = 75π un² or ≈235.5 un²
<u>Answer:</u>
The correct answer option is quadratic, because the height increases and then decreases.
<u>Step-by-step explanation:</u>
We are given the following data in the table which represents the height of an object over time:
Time (s) Height (ft)
0 5
1 50
2 70
3 48
We know that in situation where the values increase and then decreases, a quadratic model is used.
From the values given in the table, we can see that the values of height first increased and then decreased with the increase in time.
Therefore, the model used is quadratic, because the height increases and then decreases.
Answer:
The true answer is " -3 < -1.
Step-by-step explanation:
I say this because these numbers are negatives. If you put them on a number line you can see that the bigger numbers are farther from the postitives. Postitive numbers are bigger so whatever is close to them is bigger. So because (-1) is closer to them it would be greater, which is what the symbol "<' states.
We have that the answer is 7 units. A property of the perpendicular bisector of PQ (which can be used to define it) is that every point on it has the same distance from both P and Q. A proof of this is the following: Consider the shape if we join U with P and Q. There are 2 triangles, PTU and QTU. We have that the two T angles are 90 degrees, PT=TQ since T is the midpoint and the leg UT is common. Hence, by side-angle-side we have that the triangles are equal, hence UP=UQ
