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3 years ago

Please help it’s urgent!!

Mathematics

1 answer:

rewona [7]3 years ago

5 0

Answer:

Step-by-step explanation:

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Point C is between D and E and DE = 91 what is DC?

jok3333 [9.3K]

Answer:

DC=6

Step-by-step explanation:

all is shown and pictured

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3 years ago

Find the area of the shape shown below.

vovangra [49]

Answer:

I believe a=22

Step-by-step explanation:

a=4+4+4+2+8

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2 years ago

X^3 = 125 over 27 CAN I PLEASE GET HELP

Zinaida [17]

X³ = 125/27

Cube root both sides to isolate the variable:

∛x³ = ∛(125/27)

x = ∛(125/27)

∛125 = 5, ∛27 = 3

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3 years ago

15. Express 2/5 as a percentage

blsea [12.9K]

Answer:

$40\%$

Step-by-step explanation:

$\frac{2}{5} \times 100 = 40\%$

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2 years ago

Read 2 more answers

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago