A track-and-field athlete releases a javelin. The height of the javelin as a function of time is shown on the graph below. Use t
he graph to complete the statements that follow. The height of the javelin above the ground is symmetric about the line t = seconds. The javelin is 20 feet above the ground for the first time at t = seconds and again at t = seconds
For this case we must see in the graph the axis of symmetry of the given parabola. We have then that the axis of symmetry is the vertical line t = 2. Answer: The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time. We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph. Then, we must observe the moment when it returns to be 20 feet above the ground. For this, observing the graph we see that: h (3) = 20 feet Therefore, a height of 20 feet is again reached in 3 seconds. Answer: The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
In the question, Max has 9 logs in the first load. But, after the seventh load he has a total of 51 logs. So the n would be your logs in the stack, which is 51. And since there is a total of 51 logs after the seventh load. It would be 9 plus 7 in parenthesis of 51 minus one, which is 50. So 50 times 7 comes down to 350 plus nine which comes down to a total of 359.
