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sukhopar [10]
3 years ago
15

Women athletes at the University of Colorado, Boulder, have a long-term graduation rate of 67%. Over the past several years, a r

andom sample of 38 women athletes at the school showed that 21 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the University of Colorado, Boulder, is now less than 67%?
a. State the null (H0) and alternative (Ha) hypotheses.



b. Give the standard score for the data.




c. Find the P-value for this significance test.











d. Sketch your results on the standard Normal distribution










e. Summarize the conclusion in the context of this problem.
Mathematics
2 answers:
Greeley [361]3 years ago
8 0
The answer is c that’s your answer
Sergeeva-Olga [200]3 years ago
3 0
Answer: C
hope this helps out.
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For what value of x does 3^4x=27^x-3? a. –9 b. –3 c. 3 d. 9
Irina18 [472]

\bf 3^{4x}=27^{x-3}\implies 3^{4x}=(3^3)^{x-3}\stackrel{~\hfill \textit{same base, the exponents must also be the same}}{\implies 3^{4x}=3^{3(x-3)}\implies 3^{4x}=3^{3x-9}\qquad } \\\\\\ 4x=3x-9\implies x=-9

5 0
4 years ago
Please Help I Don't Understand!
asambeis [7]

Answer:

5.3

Step-by-step explanation:

Since they are similar triangles, we assume the ratio between AM/AN is equal to the ratio between MB/NC.
AM/AN = 6/8 = 3/4
If MB is 4
3/4 = MB/NC = 4/NC
3/4 = 4/NC

3NC = 16
NC = 16/3
16/3 = 5.333333

8 0
2 years ago
Help with me on these plz!!!! :)
Inessa05 [86]

Answer:

_ (repeating)

3. d=3.16

4. v=1.4

5. b=3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
People please help me in this math homework
viktelen [127]
For the last 2 questions,

1. 9/10
2. 7/12
8 0
4 years ago
Read 2 more answers
Problem 1: Given the following probabilities P(Ac) = 0.45, P(B) = 0.34, and P(B|A) = 0.23. Find the following probabilities:
-BARSIC- [3]

Answer:

P(A)=0.55

P(A and B)=P(A∩B)=0.1265

P(A or B)=P(A∪B)=0.7635

P(A|B)=0.3721

Step-by-step explanation:

P(A')=0.45

P(A)=1-0.45=0.55

P(B∩A)=?

P(B|A)=0.23

P(B|A)=(P(A∩B))/P(A)

0.23=(P(A∩B))/0.55

P(A∩B)=0.23×0.55=0.1265

P(A∪B)=P(A)+P(B)-P(A∩B)

=0.55+0.34-0.1265

=0.7635

P(A|B)=[P(A∩B)]/P(B)=0.1265/0.34 ≈0.3721

8 0
3 years ago
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