Answer:
Angle BAF and angle BAC is incorrect.
They overlap: adjacent angles do not overlap.
Answer:
x= 7
Step-by-step explanation:
1st step: Multiply the factor (outside number) with the numbers and variable(s) in the box. This results in 2(x-3) = 2x-6
2nd Step: continue the rest of the equation since there are no more brackets left so 2x-6-12=-4
3rd Step: send -12 to the other side of the equation (side changes sign changes) so it will become 2x-6=-4+12 (You are actually supposed to make the variable alone on one side of the equation so that you would be able to calculate its value)
4th step: 2x-6=8 ---> send -6 to the other side as well which will then result in 2x=14
5th step: since 2 is being multiplied by x, when you send it to the other side (to make x alone) you will divide 14 by 2 ( sign of 2 changes from multiplication to division)
Final Step: x=7
Answer:
(0, -3)
Step-by-step explanation:
Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."
Rearranging x^2+y^2+6y-72=0, we get x^2 + y^2 + 6y = 72.
x^2 is already a perfect square. Focus on rewriting y^2 + 6y as the square of a binomial: y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:
x^2 + y^2 + 6y + 9 - 9 = 72:
x^2 + (y + 3)^2 = 81
Comparing this to the standard equation of a circle with center at (h, k) and radius r,
(x - h)^2 + (y - k)^2 = r^2. Then h = 0, k = -3 and r = 9.
The center of the circle is (h, k), or (0, -3).
In Problem 13, we see the graph beginning just after x = -2. There's no dot at x = -2, which means that the domain does not include x = -2. Following the graph to the right, we end up at x = 8 and see that the graph does include a dot at this end point. Thus, the domain includes x = 8. More generally, the domain here is (-2, 8]. Note how this domain describes the input values for which we have a graph. (Very important.)
The smallest y-value shown in the graph is -6. There's no upper limit to y. Thus, the range is [-6, infinity).
Problem 14
Notice that the graph does not touch either the x- or the y-axis, but that there is a graph in both quadrants I and II representing this function. Thus, the domain is (-infinity, 0) ∪ (0, infinity).
There is no graph below the x-axis, and the graph does not touch that axis. Therefore, the range is (0, infinity).
I don't think you can solve for x unless they give you what that equation equals (for example 5x+8=7)
I'm pretty sure that is as simplified as it can be
