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muminat
3 years ago
14

How do I work this out

Mathematics
1 answer:
vazorg [7]3 years ago
7 0
Check the picture below.

make sure your calculator is in Degree mode.

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Which has a greater magnitude: owning $42 or<br>earning $12​
expeople1 [14]

Answer:

Owing $42

Step-by-step explanation:

Magnitude =|-a| where a is a value

= sqrt of(-asquared)

Therefore, $42 has the largest magnitude

5 0
3 years ago
Will give brainless ⭐️!!!
maria [59]

Answer:

It's the second on, 4 units up and 8 units to the left

5 0
3 years ago
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Find the consecutive even integers such that their sum is equal to the difference of three times the larger and two times the sm
Digiron [165]
Let the integers be x and x + 2, then
x + x + 2 = 3(x + 2) - 2x
2x + 2 = 3x + 6 - 2x
2x + 2 = x + 6
2x - x = 6 - 2
x = 4

Therefore, the integers are 4 and 6
6 0
3 years ago
Find the minimum or maximum value of the function. What is the H? (Desmos)
beks73 [17]

Answer:

Minimum: (2,4)

Step-by-step explanation:

h(x)=3(x^{2}-4x)+16

=3(x^{2}-4x+4-4)+16   (- For the balance of equation, and attention 1)

=3(x-2)^{2}-3*4+16

=3(x-2)^{2}+4

<h3>Attention:</h3>

1. (a-b)^{2}=a^{2}  -2ab+b^{2}

2. The formula for the vertex form is y = a(x-h)^{2}+k, the vertex is (h,k)

4 0
3 years ago
A kite flier wondered how high her kite was flying. She used a protractor to measure an angle of 15∘ from level ground to the ki
Nataly [62]

Answer:

12.9 yd

Step-by-step explanation:

It helps if you draw a triangle. Draw a horizontal segment. That is the ground. Now at the left end start a new segment that goes up to the right at approximately 15 degrees until it its other endpoint directly above the right endpoint of the horizontal segment. Connect these two endpoints. The vertical side on the right shows the height of the kite. The hypotenuse is the string.

For the 15-deg angle, the height of the triangle is the opposite leg, and the string is the hypotenuse. The trig ratio that relates the opposite leg tot he hypotenuse is the sine.

\sin A = \dfrac{opp}{hyp}

\sin 15^\circ = \dfrac{h}{50~yd}

(50~yd)\sin 15^\circ = h

h = (50~yd)(0.2588)

h = 12.9~yd

6 0
3 years ago
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