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Nostrana [21]
3 years ago
8

What are the solutions to this quadratic equation? -2x2+x+4=0

Mathematics
2 answers:
natka813 [3]3 years ago
8 0

Answer:

=1±33√4

Step-by-step explanation:

Bad White [126]3 years ago
3 0

Answer:

x =\frac{1+/-\sqrt{33} }{4}

Step-by-step explanation:

It wouldn't let me put the symbol in the equation but +/- is just the same thing as ±

This answer is correct on edmentum/plato

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4 years ago
In rhombus ABCD below, AC=30 cm and BD=18 cm. Find the area of the rhombus .I will give brainliest for the best and correct answ
barxatty [35]
Area of rhombus = 0.5 x D1 x D2

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Area = 0.5 x 30 x 18
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7 0
2 years ago
1. the smallest composite number is _________<br>​
Oksanka [162]

Answer:

hey dear the smallest composite number is 4

8 0
3 years ago
Solve the equation. |x + 5| = 9 {–4, 14} {–14, 4} {4, 14} {–14, –4}
inna [77]

Answer:

{-14, 4}

Step-by-step explanation:

the absolute value function only makes sure that the result always has a positive sign.

so, (x + 5) must be either +9 or -9 to make the original equation true. the absolute value would turn both into +9.

so,

x + 5 = 9

x = 4

and

x + 5 = -9

x = -14

that gives us the correct set of solutions as indicated above.

6 0
3 years ago
Here are two expressions whose product is a new expression, :
Vera_Pavlovna [14]

Answer:

1. Fill in the box with 1

2. Fill in the box with -2

Step-by-step explanation:

Expression:

(-2x^3 + [\ ]x)(x^{[\ ]}+1.5) = A

Solving (1): Fill in the box to make it a polynomial.

To make it a polynomial, we simply fill in the box with a positive integer (say 1)

Fill in the box with 1

(-2x^3 + [1]x)(x^{[1]}+1.5) = A

Remove the square brackets

(-2x^3 + x)(x^1+1.5) = A

(-2x^3 + x)(x+1.5) = A

Open bracket

-2x^4 - 3x^3 + x^2 + 1.5x = A

Reorder

A = -2x^4 - 3x^3 + x^2 + 1.5x

The above expression is a polynomial.

This will work for any positive integer filled in the box

Solving (2): Fill in the box to make it not a polynomial.

The powers of a polynomial are greater than or equal to 0.

So, when the boxes are filled with a negative integer (say -2), the expression will cease to be a polynomial

Fill in the box with -2

(-2x^3 + [-2]x)(x^{[-2]}+1.5) = A

Remove the square brackets

(-2x^3 - 2x)(x^{-2}+1.5) = A

Reorder

A = (-2x^3 - 2x)(x^{-2}+1.5)

Open brackets

A = -2x-3x^3-2x^{-1}-3x

Collect Like Terms

A = -3x^3-2x-3x-2x^{-1}

A = -3x^3-5x-2x^{-1}

Notice that the least power of x is -1.

Hence, this is not a polynomial.

3 0
3 years ago
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