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Fynjy0 [20]
2 years ago
13

Out of 200 people eating at a diner, 70% ordered

Mathematics
1 answer:
scZoUnD [109]2 years ago
4 0

Answer:

140 people

Step-by-step explanation:

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F (x) = 7 (x-1) +8 what is the value of f (1)
STALIN [3.7K]

Answer:

8

Step-by-step explanation:

f (x) = 7 (x-1) +8

For f(1) we plug 1 into x.

f(1) = 7 (1-1) +8

Simplify

f(1) = 8

8 0
3 years ago
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Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t
Viefleur [7K]

Each term differs by -68 and the first term is -68, we have:

a_{n}=a_1-68(n-1) \implies \\ a_{n}=a_1-68n+68 \implies\\ a_n=-68-68n+68 \implies \\ a_n=-68n

As an expession it's just -68n.

6 0
3 years ago
PLEASE HELP!! I will give brainiest !!!
ladessa [460]

Answer:

no f-ing clue

Step-by-step explanation:

8 0
3 years ago
Approximate: log5 4/7
Evgesh-ka [11]
   Properties of Logs

logb(x/y) = log<span>bx</span> - log<span>by</span>.

therefore

log5 (4/7)= log5 (4)- log5 (7)

<span>Solve log 5 (4) and log 5 (7)  with the base change of the logarithm</span>

<span>log 5 4 = log 4 / log 5 </span>

 Use the calculator: 

<span> <span>log 5 4 =0.8613531161 </span></span>

 log 5 7 = log 7 / log 5 

<span>log 5 7 =1.2090619551</span>

<span>log5 (4/7)= log5 (4)- log5 (7)=-0.347708839</span>

6 0
3 years ago
Read 2 more answers
5. Solve using any method.<br> y = -x + 8<br> y=x+4
vlada-n [284]

Answer:

<h2>x = 2, y = 6 → (2, 6)</h2>

Step-by-step explanation:

\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

7 0
3 years ago
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