If a factor of a quadratic function is (25+4), then the matching zero is:

Mathematics

1 answer:

cluponka [151]2 years ago

7 0

Step-by-step explanation:

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What property is 74.5*0=0

Nadya [2.5K]

74.5 x 0 = 0 belongs to the multiplication property of zero.
Because this property has a rule that any number multiplied by zero, the answer is zero.
It will not matter how big or small the number is, if it will be multiplied by zero, the answer will always be zero.
Another example:
=> 1000 x 0 = 0
=> 1524 x 0 = 0
=> .25 x 0 = 0
Notice, that even decimal numbers multiplied by zero is still zero.

7 0

2 years ago

Jesse recorded the temperatures at which two oils freeze: Oil Temperature Sesame oil −6.2 °C Peanut oil 3.1 °C Which statement a

AVprozaik [17]

Answer: C. Sesame oil freezes at a lower temperature than peanut oil because −6.2 °C < 3.1 °C

Step-by-step explanation:

Given that:

Freezing point of sesame oil = - 6.2°C

Freezing point of peanut oil = 3.1°C

Comparing the two temperatures :

Freezing(when a substance turns to solid) usually occurs at low temperatures. The temperature of sesame oil(-6 2°C) is lower than that of peanut oil(3.1°C).

Hence, it can be concluded that Sesame oil freezes at lower temperature than peanut oil.

Mathematically,

-6.2°C < 3.1°C

6 0

2 years ago

Read 2 more answers

You go shopping at a local department store with your friend and cousin. You buy one pair of jeans, four pairs of shorts, and tw

VashaNatasha [74]

Answer: Cost per pair of jeans = $ 20

Cost per pair of shorts = $12

Cost per shirt = $8

Step-by-step explanation:

Let x= cost per pair of jeans

y = Cost per pair of shorts

z= cost per shirt.

For you, total cost = x+4y+2z= 84

For your friend, total cost = 2x+y+3z=76

For cousin, total cost = x+2y+z= 52

Required system:

$x+4y+2z=84\ (i)\\ 2x+y+3z=76\ (ii)\\ x+2y+z=52\ (iii)$

from (i), $x=84-4y-2z$ (*)

put this in (ii) and (iii) we get

$2\left(84-4y-2z\right)+y+3z=76\\\Rightarrow\ -7y-z+168=76\ (iv)\\\\ 84-4y-2z+2y+z=52\\\Rightarrow\ -2y-z+84=52 \ (v)$

from (iv), $y=-\frac{z-92}{7}\ (vi)$

$\mathrm{Subsititute\:}y=-\frac{z-92}{7}\ \text{in}\ (v)$

$-2\left(-\frac{z-92}{7}\right)-z+84=52\\\\\Rightarrow\ -2\left(-\frac{z-92}{7}\right)-z=-32\\\\\Rightarrow\ -\frac{5z}{7}-\frac{184}{7}=-32\\\\\Rightarrow\ -5z-184=-224\\\\\Rightarrow\ -5z=-40\\\\\Rightarrow\ z=8$