All categories

2 years ago

Which of the following could be the equation of a line perpendicular to the line 2x−5y=7?

Mathematics

1 answer:

Over [174]2 years ago

4 0

Answer:

Step-by-step explanation:

First convert the equation to slope-intercept form:

2x - 5y = 7

-5y = -2x + 7

y = 2/5 x - 7/5

So the slope of the given line is 2/5.

So the slope of a perpendicular line will be -1/ 2/5 = -5/2.

Take B:

5x + 2y = 3

2y = -5x + 3

y = -5/2.

So its B.

You might be interested in

PLEASE HELP NEED STEP BY STEP EXPLAINATION!!!then ƒ(2) =

andrezito [222]

Swap x and y, f^-1 is and solve for y to get f^-1 the inverse of f. f(f^-1)=f^-1(f)=x is the identity as a check
f(2)=3*2+1=7 (2,7)
f^-1(7)=2 (7,2)

7 0

3 years ago

Read 2 more answers

In the figure shown, line AB is parallel to line CD. What is the

timurjin [86]

Since AB is a straight line, and straight lines are 180 degrees, you can add the two 62 degree angles.

62+62=124

180-124=56

angle x is 56 degrees

3 0

3 years ago

Pls Help Asap pls T^T

olga_2 [115]

Answer: think its c

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Look at the figure XYZ in the coordinate plane. Find the perimeter of the figure rounded to the nearest tenth.

ki77a [65]

the distance form X to Y is clearly -6 to 0 is 6 units, and 0 to 8 is 8 units, so 6 + 8 = 14 units.

now, for XZ and ZY we can simply use as stated, the distance formula to get those and then add them all to get the perimeter.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ X(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ XZ=\sqrt{[5-(-6)]^2+[8-2]^2}\implies XZ=\sqrt{(5+6)^2+(8-2)^2} \\\\\\ XZ=\sqrt{121+36}\implies \boxed{XZ=\sqrt{157}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad Y(\stackrel{x_2}{8}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ZY=\sqrt{(8-5)^2+(2-8)^2}\implies ZY=\sqrt{9+36}\implies \boxed{ZY=\sqrt{45}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{perimeter}{14+\sqrt{157}+\sqrt{45}}\qquad \approx \qquad 33.2$

6 0

3 years ago

-3(x+4)-8x>21 solve this equation

stellarik [79]

Answer:

the answer:

Step-by-step explanation:

pls, crown or star. <3

4 0

2 years ago

Read 2 more answers