Hey!
Switch it around and it becomes:
First find 18 ÷ -6
Positive ÷ negative OR negative ÷ positive is always negative.
That leaves you with:
Switch that around and it becomes:
Find -3 + 5
That leaves you with:
Divide both sides by 2 to leave <em>x</em> alone
i can't really see the image but i'm sure it's pretty cool (:
The area of a circle uses the radius of a circle, which is 1/2 the diameter.
In the calculation the radius is squared.
Since the diameter of the larger circle is twice as large the radius would be 2 times.
2 squared would be: 2^2 = 4
This means the area of the larger circle is 4 times larger which would make the ratio 4:1
I'm pretty sure it is.
If i'm wrong, I'm truly sorry
Answer:
a) 615
b) 715
c) 344
Step-by-step explanation:
According to the Question,
- Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams
- Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.
Z = (x - mean)/standard deviation
Now,
For x = 4171, Z = (4171 - 3311)/860 = 1
- P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.
Next, multiply that by the sample size of 732.
- Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171
- For part b, use the same method except x is now 1591.
Z = (1581 - 3311)/860 = -2
- P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.
- For part c, we now need to get two Z scores, one for 3311 and another for 5031.
Z1 = (3311 - 3311)/860 = 0
Z2 = (5031 - 3311)/860= 2
P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772
approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.
