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3 years ago

Helppppp me please i need the answer fast <3

Mathematics

2 answers:

dimulka [17.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

bonufazy [111]3 years ago

3 0

Answer:

|5| = 5

Step-by-step explanation:

Absolute value can be seen as the distance between a number and zero. It is always a positive number. 5 is 5 units away from 0. |5| = 5, and |-5| would also be 5. It's important not to get absolute value confused with opposites.

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Nolan rides his bike 63 miles in 270 minutes. What is his average speed in miles per hour?

s2008m [1.1K]

63 miles in 270 minutes will mean that nolan rides his bike at a distance of 63/270 miles in one minute.
there are 60 minutes in an hour. So to find out the distance he covers in 1 hour, 63/270 × 60 will give you 14 miles.
Since the question is asking for the average speed, nolan rides his bike at 14 miles per hour i think.

4 0

4 years ago

Need help with homework plz, also will give brainiest to who ever gets the question right first!

Degger [83]

Answer: x = 5/7

Step-by-step explanation:

The numerator is the power, while the denominator is the index (thing next to radical).

7 0

3 years ago

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$