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Amanda [17]
2 years ago
15

A photocopier can print 12 copies in 18 seconds. At this rate, how many copies can it print in 42 seconds?​

Mathematics
2 answers:
nata0808 [166]2 years ago
8 0
28 copies !!!!!!! In 42 second
Dovator [93]2 years ago
8 0

Answer:

It should be 28 copies

Step-by-step explanation:

If you divide 42 by 18 it gives you 2.33333333

If you multiply 12 by 2.33333333 it gives you 28

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How do I find the value of Q in the following systems so my solution to the system is
vesna_86 [32]
Hello,

if the solution is infinite : the line x-3y=4 ,
so there is one line and not 2

==>x-3y=4 multiplied by 2
2x-6y=8=Q

Q=8

4 0
3 years ago
FIRST TO ANSWER GETS BRALYIST<br> good luck :-)
Ratling [72]

Answer:

My answer is 20ft I'm not really sure but hope this helps

7 0
2 years ago
I WOULD LOVE IF SOMEONE CAN ANSWER THIS QUESTION FOR ME!
postnew [5]

Answer:

32 cm^3

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Does anyone understand this
melomori [17]
I hope this helps you

7 0
3 years ago
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