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AleksandrR [38]
3 years ago
6

Adriel watched a 1 -h movie on TV. Nadir watched 3 half-hour sitcoms. Who watched more TV? How do you know?

Mathematics
1 answer:
MrMuchimi3 years ago
7 0
Nadir cause it’s 3 half hours so that’s a hour and thirty minutes of tv
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Plz help 10 pts <br> X=<br> 4<br> 6<br> 12
Anit [1.1K]

Answer:

x = 12

Step-by-step explanation:

The product of the length of the secant segment and its external part equals the square of the length of the tangent segment.

3*x = 6^2

3x = 36

Divide each side by 3

3x/3 = 36/3

x = 12

4 0
3 years ago
What is the average of $190,258.50; $152,698.00; $122,753.00; $220,523.00; $231,951.00?
RoseWind [281]
If you add it will be 807,683.5
if you multiply it will be 1.82083248E+25
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8 0
3 years ago
Find the area of a parallelogram with base 15 yards and height 21 2/3 yards​
SpyIntel [72]

Answer:

325 yards

Step-by-step explanation:

To find the area of a parallelogram, it is base times height.

Therefore, it is 15 times 65/3 which gives you 325.

I changed 21 2/3 to 65/3 so I could put it into the calculator the easiest. They are the same fraction.

4 0
4 years ago
A card is selected at random from an ordinary deck of 52 cards. What is the probability that it is either an ace or a spade
tamaranim1 [39]

Answer: 4/13

Step-by-step explanation:

Number of cards in a deck = 52

Number of spades = 13

Number of aces = 4

Number of ace of spade = 1

Probability of either a spade or an ace :

P(spade or ace) = P(spade U ace)

P(spade U ace) = p(spade) + p(ace) - p(spade n ace)

Probability = required outcome / Total possible outcomes

P(spade) = 13 / 52

P(ace) = 4 / 52

P(spade n ace) = 1 / 52

P(spade U ace) = p(spade) + p(ace) - p(spade n ace)

= 13/52 + 4/52 - 1/52

= 16 / 52 = 4 /13

8 0
3 years ago
Y= -7x-2<br> y+ 3 = -7x + 1<br> (<br> 2,3)<br> no solution<br> an infinite number of solutions
Naya [18.7K]

Answer:

Infinite number of solutions.

Step-by-step explanation:

y = -7x - 2

y + 3 = -7x + 1

Subtract 3 from both sides:

y = -7x - 2

- this is the same as the first equation.

We can put any number of valid combinations of x and y into this equation.

So there are infinite solutions.

8 0
3 years ago
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