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3 years ago

Y= -7x-2 y+ 3 = -7x + 1 ( 2,3) no solution an infinite number of solutions

Mathematics

1 answer:

Naya [18.7K]3 years ago

8 0

Answer:

Infinite number of solutions.

Step-by-step explanation:

y = -7x - 2

y + 3 = -7x + 1

Subtract 3 from both sides:

y = -7x - 2

- this is the same as the first equation.

We can put any number of valid combinations of x and y into this equation.

So there are infinite solutions.

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In which quadrant does the point (-4,15) lie

Ivanshal [37]

Quadrant one

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3 years ago

Mr. Rudd built a cabin with 351 logs, and his friend built a cabin with 113 logs. About how many logs did the two of them use

seropon [69]

Answer:

464

Step-by-step explanation:

351 + 113. Add them both together to get your answer.

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3 years ago

Half a number is at least 2 units from 20. write the sentence as an absolute value inequality

Anuta_ua [19.1K]

Answer:

|1/2x - 20| ≥ 2

Step-by-step explanation:

The number is half of two and at least two units away.

8 0

3 years ago

Read 2 more answers

Is v = -1 / 3 a solution of 9v-2= 3v?

Gre4nikov [31]

Answer:

No, -1/3 is not a solution

Step-by-step explanation:

See if it is a solution by plugging in -1/3 as v and seeing if the equation is correct:

9v - 2 = 3v

9(-1/3) - 2 = 3(-1/3)

-3 - 2 = -1

-5 = -1

-5 $\neq$ -1

So, since the equation is incorrect, -1/3 is not a solution.

4 0

3 years ago

A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample

8090 [49]

Answer:

Step-by-step explanation:

Step(i):-

Given first random sample size n₁ = 500

Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

First sample proportion

$p^{-} _{1} = \frac{65}{500} = 0.13$

Given second sample size n₂ = 700

Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.

second sample proportion

$p^{-} _{2} = \frac{133}{700} = 0.19$

Level of significance = α = 0.05

critical value = 1.96

Step(ii):-

Null hypothesis : H₀: There is no significance difference between these proportions

Alternative Hypothesis :H₁: There is significance difference between these proportions

Test statistic

$Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$

where

$P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165$

Q = 1 - P = 1 - 0.165 = 0.835

$Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }$

Z = -2.76

|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance

Null hypothesis is rejected at 0.05 level of significance

Alternative hypothesis is accepted at 0.05 level of significance

Conclusion:-

There is there is a difference between these proportions at α = 0.05

3 0

3 years ago