X=[(x+60°)-20°]/2
x=(x+60°-20°)/2
x=(x+40°)/2
Solving for x: Multiplying both sides of the equation bu 2:
2x=2(x+40°)/2
2x=x+40°
Subtracting x both sides of the equation:
2x-x=x+40°-x
x=40°
Answer: x=40°
In B 5^2 = 25. There is no x anywhere.
In C f(x) = 2/x is a function of a reciprocal, not a quadratic.
In D f(x) = 2x^3 + 3x^2 - 5 is a cubic. A cubic is not a quadratic. The highest power of a quadratic is x^2
That leaves A. When you expand the brackets, you get
3(x^2 + 3x- 4x - 12)
2(x^2 - x - 12) when you remove the brackets you get
2x^2 - 2x - 24. The highest power of x is x^2. This is your quadratic.
A<<<< answer.
Answer:
18 cm
Step-by-step explanation:
you multiply 6 by 3 to get the answer