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4 years ago

Each time the 5 moves one place to the left, it is worth ___________as

Mathematics

2 answers:

joja [24]4 years ago

7 0

Answer:

A. 10 times

Step-by-step explanation:

svp [43]4 years ago

4 0

Answer:

A. Ten times.

Step-by-step explanation:

If it was one place to the <em>right</em>, it would have been one-tenth, so that's gone. If it was moved twice in place of either direction, it would be hundredths, so those are also eliminated. So, It's 10 times.

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HELP!! I WILL NAME BRAINLIEST!If f(x) = (x + 7), which of the following is g(x) based on the translation?

expeople1 [14]

Answer:

g(x) = (x + 5)2

Step-by-step explanation:

5 0

3 years ago

A building across the street casts a shadow that is 24 feet long your friend is 6 feet tall and casts a shadow that is 4 feet lo

matrenka [14]

6/4=b/24

1.5=b/24

24(1.5)=b

36=b

Building is 36 ft tall

8 0

4 years ago

Read 2 more answers

If one kilogram is 2.2 pounds how many kilograms would it make for 11 pounds

Mila [183]

Answer:

5 kg

Step-by-step explanation:

To solve this problem, we can use the rule of three.

In fact, we know that:

- 1 kilogram is equivalent to 2.2 pounds

- The ratio between the mass in kilograms and in pounds is constant for every value of the mass

- Therefore, the mass in kilograms corresponding to 11 pounds can be found by writing the following equation:

$\frac{1 kg}{2.2 p}=\frac{x}{11 p}$

Where

x is the mass in kilograms corresponding to 11 pounds.

Solving the equation for x, we find:

$x=\frac{(11p)(1kg)}{2.2p}=5 kg$

5 0

3 years ago

A submarine changes its position by −7 meters every second.

IgorLugansk [536]

The correct anwer is -21 and how i got that is by taking -7*300 to get -21 as my answer let me know if it helped any...

5 0

3 years ago

Read 2 more answers

A. Do some research and find a city that has experienced population growth.

horrorfan [7]

A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation $N_{t} =N _{0}e^{rt}$
where:
$N(t)$ is the population after $t$ years
$N_{0}$ is the initial population
$t$ is the time in years
$r$ is the growth rate in decimal form
$e$ is the Euler's constant
We now for our investigation that $N(t)=238300$ , $N_{0} =192157$ , and $t=10$ ; lets replace those values in our equation to find $r$ :
$238300=192157e^{10r}$
$e^{10r} = \frac{238300}{192157}$
$ln(e^{10r} )=ln( \frac{238300}{192157} )$
$r= \frac{ln( \frac{238300}{192157}) }{10}$
$r=0.022$
Now lets multiply $r$ by 100% to obtain our growth rate as a percentage:
$(0.022)(100)$ =2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that $N(t)=713777$ , $N_{0} =951307$ , and $t=10$ . Just like before, lets replace those values into our equation to find $r$ :
$713777=951307e^{10r}$
$e^{10r} = \frac{713777}{951307}$
$ln(e^{10r} )=ln( \frac{713777}{951307} )$
$r= \frac{ln( \frac{713777}{951307}) }{10}$
$r=-0.029$
$(-0.029)(100)$ = -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: $N(t)=192157e^{0.022t}$ .
Final equation from point B: $N(t)=951307e^{-0.029t}$
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations $N(t)=192157e^{0.022t}$ and $N(t)=951307e^{-0.029t}$ and solve for t:
$192157e^{0.022t} =951307e^{-0.029t}$
$\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1$
$e^{0.051t} = \frac{951307}{192157}$
$ln(e^{0.051t})=ln( \frac{951307}{192157})$
$t= \frac{ln( \frac{951307}{192157}) }{0.051}$
$t=31.36$
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be $2(951307)=1902614$ . Now we can rewrite our equation as: $N(t)=1902614e^{-0.029t}$ . The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
$192157e^{0.022t} =1902614e^{-0.029t}$
$\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1$
$e^{0.051t} = \frac{1902614}{192157}$
$ln(e^{0.051t} )=ln( \frac{1902614}{192157} )$
$t= \frac{ln( \frac{1902614}{192157}) }{0.051}$
$t=44.95$
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit.

8 0

4 years ago