Question

Right triangle ABC is shown.

Answer 1

Answer:

$\sin(50^o) = \frac{3}{c}$

Step-by-step explanation:

Given

See attachment for triangle

Required

Expression to solve c

To solve for c, we simply calculate the sine of angle at B

i.e.

$\sin(50^o) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(50^o) = \frac{3}{c}$

Make c the subject

$c = \frac{3}{\sin(50^o)}$