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pantera1 [17]
3 years ago
7

This morning, Josh's car had 19.22 gallons of fuel. Now, 5.3 gallons are left. How much fuel did Josh use?​

Mathematics
2 answers:
AleksAgata [21]3 years ago
8 0

Answer:

13.92 gallons

Step-by-step explanation:

To figure this out you need to do 19.22-5.3 because 19.22 is how much fuel you started with and 5.3 is how much you have now. So by subtracting them, you can find the amount of fuel he used. 19.22-5.3=13.92

Viefleur [7K]3 years ago
3 0

Answer:

He used 13.92 gallons of gas.

Step-by-step explanation:

19.22-5.3=13.92

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Your family went on a road trip. They drove for 12 hours in one day. Your mom drove 5 / 6 of that time. How much of the time did
Viefleur [7K]

Answer:

10

Step-by-step explanation:

The first thing you do is:

12 % 6 = 2

Then you have to:

2 x 5 = 10

You divide the denominator then multiply it by the Numerator

7 0
3 years ago
Find m ABC (2x+14) (x+7) ​
Orlov [11]

Answer:

Last option 30°

damm sure about it

Step-by-step explanation:

value of x is 23 but value of Angle ABC will be x +7 i.e. 30

6 0
3 years ago
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Y= mx + b what is b?
PSYCHO15rus [73]
Y=mx+b is Slope Intercept Form, where m represents the slope and b represents the y-intercept.

The y-intercept is the value of y when x equals 0, and can be visualized on a graph as the point on the line when it crosses the y-axis.
8 0
3 years ago
The International Space Station orbits at an altitude of about 250 miles about Earth’s surface. The radius of Earth is approxima
Hatshy [7]
In this case we are dealing with the pythagorean theorm involving right angled triangles. This theorm states that a^2 + b^2 = c^2 which means the square of the hypotenuse (side c, opposite the right angle) is equal to the square of the remaining two sides.

In this case we will say that a = 3963 miles which is the radius of the earth. c is equal to the radius of the earth plus the additional altitude of the space station which is 250 miles; therefore, c = 4213 miles. We must now solve for the value b which is equal to how far an astronaut can see to the horizon.

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8 0
3 years ago
Given the sequence 8, 12, 16, 20, 24, what is the sum of the 31st and 19th terms?
erica [24]

Answer:

First term (a) =8

Common difference (d)= t2-t1

=12-8

=4

Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}

= 31/2{2×8+(31-1)4}

=31/2{16+(30×4)

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Step-by-step explanation:

Similarly use 19 as (n) for the 19th term

7 0
2 years ago
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