1.The trait is recessive. This means both your parents were carries, but did not show the trait. For example, B represents the allele, you're parents would have to both be Bb. This means that they are carriers, and you could have inherited either BB/Bb/bb - you actually inherited bb, which means because its a recessive trait you will show the trait.
2. For your children, it depends on who you have them with. Because you're bb, you will definitely pass on the b allele, so any child you have would be a carrier and could potentially have the trait. If you have a child with someone BB, all your offspring will be Bb (carriers- as the kid gets one allele form each parent). If you have a child with someone who is bb, all your kids would definitely have the trait. However, if you have a child with someone who as Bb, then the four outcomes are Bb Bb bb bb, so there would be a 50% chance of your kid having the trait.
Hope this helps!! :)
The enzyme Taq polymerase is required in the PCR process because it is the main enzyme that synthesizes the new DNA strands complementary to the template strand and without the activity of this enzyme the PCR will be useless and it cannot make the copy of the given strand in any way. Thus, this enzyme is very much necessary for the efficient working of the PCR.
Polymerase Chain Reaction is a very efficient technique that can able to detect and copy even a small amount of DNA by performing a set of reactions at different temperatures.
The PCR process begins with the denaturing of the template strand at 95°C, followed by annealing in which the appropriate primers bind to the single strands of DNA at 50-56°C, followed by extension at 72°C in which the thermostable Taq polymerase synthesizes the strand complementary to the template DNA.
Learn more about PCR here
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The process of making multiple copies of a gene by inserting it into a host genome and culturing the host is an example of gene cloning.
Answer:
Although more offsprings are produced by the process of external fertilization but the process of internal fertilization is more efficient as compared to external fertilization. This is because, in external fertilization, it is more difficult for the sperm to find the egg and fertilize it. Even after fertilization, it might be that the zygote gets eaten up by a predator. There are none such risks in internal fertilization. The zygote is protected during the internal fertilization which makes this process more efficient.
Answer:
The oxygen dissociation curve represents the percentage saturation of Hb with oxygen at different partial pressure of oxygen. The different partial pressures gives sigmoid shapes to the curve. When this curves shifts to right, it indicates low affinity or binding of oxygen by the Hb. it also indicates the unloading or releases of Oxygen by Hb molecules at condition of low pressure. e,g in the muscles during strenuous exercise.However, when the curve shifts to the left, this indicate high affinity for oxygen, great binding, at high partial pressure of oxygen.e,g in the lungs to take oxygen and releases CO2.
Therefore in this scenario, the statement -. <u>During strenuous exercise, the oxygen-hemoglobin dissociation curve shifts to the right.</u> is correct. because oxygen is needed by the muscles therefore ,oxygen should be less binded by Hb, decrease affinity and easily unloaded to muscles.
<u>The statement </u>This rightward shift reflects an increase in the affinity of hemoglobin for oxygen and favors loading of O2 into hemoglobin in the lungs is wrong.
As explained above the rightwards shift indicated low affinity of Hb for oxygen(unloading)and favours unloading at the muscles because during strenuous exercise the partial pressure of oxygen is very low(but that of CO2 high) in the muscles which favours low oxygen molecules binding by Hb, and easy release to respiring cells.
Explanation:
