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Liono4ka [1.6K]
3 years ago
7

1 1/3 x 1 4/9 the product is

Mathematics
2 answers:
natka813 [3]3 years ago
8 0

Answer:

52/27

Step-by-step explanation:

Maksim231197 [3]3 years ago
4 0

Answer:1 25/27

Step-by-step explanation:

You might be interested in
Will mark brainliest! Questions are in the picture!
serg [7]
Option a, c,d are correct.
step-by-step explanation:
from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have
tz=sz(given)
bz=zb(common)
therefore, by rhs rule,δtzb ≅δszb
by cpctc, sz≅tz
also, from δctz and δasz,
tz=sz(given)
∠tcz=∠saz(90°)
by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz
also,from δasz and δzsb,
zs=sz(common)
∠zbs=∠saz=90°
by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb
hence, option a, c,d are correct.
5 0
2 years ago
GC - If the principal amount of money put into a bank is $2000 with a 3.5% rate compounded quarterly, what is the amount after 6
alisha [4.7K]

Given:

Principal amount = $2000

Rate of interest = 3.5% compounded quarterly.

Time = 6 years

To find:

The amount after 6 years.

Solution:

The formula for amount after compound interest is:

A=P\left(1+\dfrac{r}{n}\right)^{nt}

Where, P is principal, r is rate of interest in decimal, n is the number of time interest compounded in an year and t is the number of years.

The interest is compounded quarterly, so n=4.

Substituting P=2000,r=0.035,n=4,t=6, we get

A=2000\left(1+\dfrac{0.035}{4}\right)^{4(6)}

A=2000\left(1+0.00875\right)^{24}

A=2000\left(1.00875\right)^{24}

A=2465.10340

Approximate the value to the nearest hundredth.

A\approx 2465.10

The amount after 6 years us $2465.10. Therefore, the correct option is A.

4 0
3 years ago
Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Compute the proba
sergejj [24]

Answer:

P [ 55 ≤ X ≤ 70 ] = 23.55 %

Step-by-step explanation:

We know:

μ₀ = mean of population              σ  = standard deviation  

We begin for calculating the probability of X ≤ 55 so

Step 1:

μ₀  = 50              σ = 7

×₁    =   ( μ - μ₀ ) ÷ σ   ⇒  ×₁  = (55-50) ÷ 7     ⇒  ×₁  = 5 ÷ 7    ×₁ = 0.7143

We look z table and we have to interpolate

value (closest smaller Than    ×₁   0.71   and closest bigger than ×₁   0.72

The associated area for these point are:   0.7611 and 0.7642

Taking diferences and by rule of three

0.01             ⇒  0.0031

0.0042        ⇒      Δ          Δ = 0.0013     and  Area for ×₁  = 0.7624

That is the probability of  X ≤ 55

Now we have to find the probability of X ≤ 70

We procede as in step 1

μ₀  = 50             σ = 7

×₂    =   ( μ - μ₀ ) ÷ σ   ⇒  ×₂  = (70-50) ÷ 7     ⇒  ×₂  = 20 ÷ 7    ×₂ = 2.8571

We look z table and we have to interpolate

for 2.85    ⇒ 0.9978 (area)              2.8571 - 2.85  = 0.007

for 2.86    ⇒ 0.9979 (area)

Therefore by rule of three we have

0.01      ⇒    0.0001

0.007   ⇒        Δ                       Δ = 0.00007

And area for      ×₂ = 2.8571      is  equal to 0.99787   and the probability of

X ≤ 0.99787   or    99.79

Now if we look the annex drawing (the area we are looking for is enclose for the values x₁   and ×₂  (pink area) and is the diference between these two areas

So   P [ 55 ≤ X ≤ 70 ]  is 99.79 % - 76.24 %  = 23.55

 

4 0
3 years ago
Isn't it 46? someone correct me if I'm wrong<br><br> Brainliest + easy points!
Cerrena [4.2K]
Yep! :) You got it.

The answer is 46.
6 0
3 years ago
Read 2 more answers
2 hours after a freight train leaves delhi a passenger train leaves the same station traveling in the same direction at an avera
insens350 [35]

The average speed of the freight train was 10.67 km/hr.

<h3>What is average speed?</h3>

The average speed is the total distance traveled by the object in a particular time interval.

Now it is given that,

Average speed of the passenger train = 16 km/hr

Time taken by passenger train to overtake the freight train = 4 hours

So, the distance between two trains = Average speed of the passenger train * Time taken by passenger train overtake the freight train

⇒ distance between two trains = 16 * 4 = 64 km

Thus, Distance to be covered by freight train = 64 km

Since, freight train leaves the same station in the same direction after 2 hours.

Hence, total time taken to cover 64 km by freight train = 2 + 4

                                                                                             = 6 hours

⇒ Average speed of the freight train = Distance covered by freight train/total time taken to cover 64 km

⇒ Average speed of the freight train = 64/6 km/hr

⇒ Average speed of the freight train = 32/3 km/hr

or, Average speed of the freight train = 10.67 km/hr

Thus, the average speed of the freight train was 10.67 km/hr.

To learn more about average speed:

brainly.com/question/14556289

#SPJ4

5 0
1 year ago
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