Answer: The first experiment has M probabilities, and the second has I(m) outcomes, that depends on the result of the first.
And lets call m to the result of the first experiment.
If the outcome of the first experiment is 1, then the second experiment has 1 possible outcome.
If the outcome of the first experiment is 2, then the second experiment has 2 possibles outcomes.
If the outcome of the first experiment is M, then the second experiment has M possibles outcomes.
And so on.
So the total number of combinations C is the sum of all the cases, where we exami
1 outcome for m = 1
+
2 outcomes for m=2
+
.
.
.
+
M outcomes for m = M
C = 1 + 2 + 3 + 4 +...´+M
Answer:
Step-by-step explanation:
utilise the Foil method to expand brackets:
F - mulply the first terms (x and x)
O - multiply the outside terms ( x and -2)
I - multiply the inside terms (5 and x)
L - multiply the last terms (5 and -2)
Then add them as following:
Then combine like terms:
Note that when dividing, and the base is the same, you can subtract the power signs.
(5^5)/(5^2) = 5^(5 - 2)
5 - 2 = 3
5^3 = a^b
Simplify.
5^3 = 5 x 5 x 5
5 x 5 x 5 = 125
c = 125
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125 is your answer
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hope this helps
The answer is -5x + 4y = -20
Answer:
Step-by-step explanation: 6,2,3
