3 radical 4n ... how can I do this bro
1 answer:
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Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π and cos A = cos B · cos C
scratchwork:
A + B + C = π
A = π - (B + C)
cos A = cos [π - (B + C)] Apply cos
= - cos (B + C) Simplify
= -(cos B · cos C - sin B · sin C) Sum Identity
= sin B · sin C - cos B · cos C Simplify
cos B · cos C = sin B · sin C - cos B · cos C Substitution
2cos B · cos C = sin B · sin C Addition
Division
2 = tan B · tan C
<u>Proof LHS → RHS</u>
Given: A + B + C = π
Subtraction: A = π - (B + C)
Apply tan: tan A = tan(π - (B + C))
Simplify: = - tan (B + C)
Substitution: = -(tan B + tan C)/(1 - 2)
Simplify: = -(tan B + tan C)/-1
= tan B + tan C
LHS = RHS: tan B + tan C = tan B + tan C
Answer:
<h3>Angle 6 = 101°</h3><h3>Angle 5 = 79°</h3><h3>Angle 7 = 79</h3>Step-by-step explanation:
Angle 6 will 101°
This is because we can see that Angle 4 is alternate interior angle to Angle 6 and alternate interior angles are always equal.
<h2>So angle 6 will be 101°</h2>Angle 7 = 79°
Here we can see that Angle 6 and angle 7 are supplementary which means it has a measure of 180°
So the value of Angle 7 will be
Angle 5 = 79°
Angle 7 and Angle 5 is vertically opposite to each other and we know that vertically opposite angles are always equal so the measure will be 79°
<h3>Hence the measure of Angle 5 will be 79°</h3>