Answer:
39
Step-by-step explanation:
Let x be tens place digit and y be units place digit.
Therefore, required number = 10x + y
On reversing the digits number so obtained = 10y + x
According to the given information:
10y + x = 10x + y + 54
10y + x - 10x - y = 54
9y - 9x = 54
9(y - x) = 54
y - x = 54/9
y - x = 6
y = x + 6...... (1)
Since, sum of the digits is 12.
Therefore, x + y = 12....(2)
From equations (1) & (2)
x + x + 6 = 12
2x = 12 - 6
2x = 6
x = 6/2
x = 3
y = x + 6 = 3 + 6 = 9...[from eqn (2)]
10x + y = 10*3 + 9 = 30 + 9 = 39
Thus, the required number is 39.
Answer:
x = 23
Step-by-step explanation:
x=heavy equipment
y= general labor
x+y=38
x=38-y
134x + 92y=4756
134(38-y)+92y =4756
5092-134y+92y=4756
-42y = -336
y = -336/-42 = 8
x=38-8=30
check 30*134 =4020
8*92 = 736
4020+736 = 4756
8 general laborers
30 heavy equipment operators
There are 10 possible number on the first wheel, their would be 9 possible on the second, 8 on the thrid, 7 on the frouth, and 6 on the fifth.
So, 10 * 9 * 8 * 7 * 6 = 30,240 possible combinations without repeating numbers.