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lorasvet [3.4K]
3 years ago
11

To one-one functions g and h are defined as follows.

Mathematics
1 answer:
Andreyy893 years ago
6 0

Answer:

  • 9
  • (x-8)/3
  • -1

Step-by-step explanation:

The inverse function for a set of ordered pairs can be found by swapping the x- and y-coordinates in each pair.

  g^{-1}(-1)=9\qquad\text{from the $g(x)$ ordered pair $(9, -1)$}

__

The inverse of a function expressed algebraically can be found by swapping the x- and y-variables and solving for y.

  h^{-1}(x)\qquad\text{is found from }x=h(y)\\\\x=3y+8\\x-8=3y\\\\y=\dfrac{x-8}{3}\\\\\boxed{h^{-1}(x)=\dfrac{x-8}{3}}

A function of its own inverse returns the original value:

  \boxed{\left(h\circ h^{-1}\right)(-1)=-1}

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Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

3 0
3 years ago
Read 2 more answers
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2 years ago
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Let me know if there is more to the problem!

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3 years ago
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