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lapo4ka [179]
3 years ago
11

Helllllllpppppppp Plllleeeeaaase I have a test!!!!

Mathematics
1 answer:
Tresset [83]3 years ago
3 0
Do you still need it
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PLEASE help me I beg you
Likurg_2 [28]

Answer:

:

pls, don't do that

Step-by-step explanation:

3 0
3 years ago
A jar contains 2 orange, 4 green, 2 white and 2 black balls. What is the probability of drawing an orange ball without putting i
KonstantinChe [14]

Answer:

2/45

Step-by-step explanation:

We are told that:

A jar contains 2 orange, 4 green, 2 white and 2 black balls.

The total number of balls in the jar is calculated as:

2 orange balls + 4 green balls + 2 white balls + 2 black balls = 10 balls

The probability of drawing an orange ball = P(Orange) = 2/10

The probability of drawing a black ball = P(Black) = 2/10

Therefore, the probability of drawing an orange ball without putting it back, then drawing a black ball is calculated as:

2/10 × 2/9 = 4/90

= 2/45

7 0
3 years ago
Find sin(a+B)
diamong [38]

Answer:

Cos A=5/13

we have

Cos² A=1-Sin ²A

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A=\sqrt{144/169}=12/13

again

Tan B=4/3

P/b=4/3

p=4

b=3

h=\sqrt{3²+4²}=5

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

<u>S</u><u>i</u><u>n</u><u>(</u><u>A</u><u>+</u><u>B</u><u>)</u><u>:</u><u>s</u><u>i</u><u>n</u><u>A</u><u>c</u><u>o</u><u>s</u><u>B</u><u>+</u><u>C</u><u>o</u><u>s</u><u>A</u><u>s</u><u>i</u><u>n</u><u>B</u>

<u>n</u><u>o</u><u>w</u><u> </u>

<u>substitute</u><u> </u><u>value</u>

<u>Sin(A+B):</u>12/13*3/5+5/13*(-4/5)=36/65-4/13

<u>=</u><u>1</u><u>6</u><u>/</u><u>6</u><u>5</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>

6 0
3 years ago
4 bags of cement do 18m(squared), how many m(squared) can be done with 7 bags ?
Elis [28]
I think 7 bags do 31.5 m squared
4 0
3 years ago
If X squared equals 16 then X equals 4
AfilCa [17]
That would be correct because if x times x =16 than that means that the square root of 16 is 4
6 0
3 years ago
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