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Anna71 [15]
10 months ago
10

5 + kx = 17Solve for x

Mathematics
2 answers:
gtnhenbr [62]10 months ago
6 0

1) To solve for x, is to leave the x on the left side the other variables on the right along with the constants, like this

\begin{gathered} 5\text{ +kx =17} \\ kx\text{ =17-5} \\ x=\frac{17-5}{k} \end{gathered}

Note that, we subtracted 5 and then divided by x.

makkiz [27]10 months ago
6 0

Answer:

5+kx=17

kx=17-5

kx=12

x= 12/k

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Equilateral triangle ABC has an area of \sqrt{3}√ ​3 ​ ​​ . If the shaded region has an area of \piπK − \sqrt{3}√ ​3 ​ ​​ , what
Liono4ka [1.6K]

Answer:

The value of k = 4/3

Step-by-step explanation:

* Lets explain how to solve the problem

- An equilateral triangle ABC is inscribed in a circle N

- The area of the triangle is √3

- The shaded area is the difference between the area of the circle

  and the area of the equilateral triangle ABC

- The shaded are = k π - √3

- We need to find the value of k

* <u><em>At first lets find the length of the side of the Δ ABC</em></u>

∵ Δ ABC is an equilateral triangle

∴ Its area = √3/4 s² , where s is the length of its sides

∵ The area of the triangle = √3

∴ √3/4 s² = √3

- divide both sides by √3

∴ 1/4 s² = 1

- Multiply both sides by 4

∴ s² = 4 ⇒ take √ for both sides

∴ s = 2

∴ The length of the side of the equilateral triangle is 2

* <u><em>Now lets find the radius of the circle</em></u>

- In the triangle whose vertices are A , B and N the center of the circle

∵ AN and BN are radii

∴ AN = BN = r , where r is the radius of the circle

∵ The sides of the equilateral angles divides the circle into 3 equal

   arcs in measure where each arc has measure 360°/3 = 120°

∵ The measure of the central angle in a circle equal the measure

  of the its subtended arc arc

∵ ∠ANB is an central angle subtended by arc AB

∵ The measure of arc AB is 120°

∴ m∠ANB = 120°

- By using the cosine rule in Δ ANB

∵ AB = 2 , AN = BN = r , m∠ANB = 120°

∴ (2)^{2}=r^{2}+r^{2}-2(r)(r)cos(120)

∴ 4=r^{2}+r^{2}-2(r)(r)(-0.5)

∴ 4=r^{2}+r^{2}-(-r^{2})

∴ 4=r^{2}+r^{2}+r^{2}

∴ 4=3r^{2}

- Divide both sides by 3

∴ r^{2}=\frac{4}{3}

- Take square root for both sides

∴ r = 2/√3

* <u><em>Lets find the value of k</em></u>

∵ Area circle = πr²

∵ r = 2/√3

∴ Area circle = π(2/√3)² = (4/3)π

∵ Area shaded = area circle - area triangle

∵ Area triangle = √3

∴ Area shaded = (4/3) π - √3

∵ Area of the shaded part is π k - √3

- Equate the two expressions

∴ π k - √3 = (4/3) π - √3

∴ k = 4/3

* The value of k = 4/3

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3 years ago
Sally works in a cell phone store. She is paid a weekly salary of $80 plus $5.25 for
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Answer:

First, let's define some variables.

x = # of cell phones sold.

y = total weekly income.

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a is the correct answer choice.

Step-by-step explanation:

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When ms Thelma turned one her oven ,the temperateure inside was 70 degress. The temputure began to rised at a rate of 40 per min
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Answer:

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350-70=280

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It took Ms. Thelmas oven to heat up from 70 degrees to 350 degrees in 7 minutes.

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Solve equation, check for extraneous solutions
fiasKO [112]

Start with

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We observe that both fractions are not defined if n=0. So, we will assume n \neq 0.

We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

1=\dfrac{3}{3n^2}+\dfrac{n^2-4n-5}{3n^2} = \dfrac{n^2-4n-2}{3n^2}

We multiply both sides by 3n^2:

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We move everything to one side and solve the quadratic equation:

2n^2+4n+2=0 \iff 2(n^2+2n+1)=0 \iff 2(n+1)^2=0 \iff n+1=0 \iff n=-1

We check the solution:

1=\dfrac{1}{1}+\dfrac{1+4-5}{3} \iff 1 = 1+0

which is true

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The definition of parallel lines requires the undefined terms line and plane, while the definition of perpendicular lines requir
iVinArrow [24]
The characteristics of these geometric figures create:
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2. While perpendicular lines are two lines that will meet at a 90-degree angle or right angle.
3 0
3 years ago
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