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tensa zangetsu [6.8K]
2 years ago
13

Write an equation in slope-intercept form: (1,6) and (2,3) are on the line

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
5 0

Step-by-step explanation:

eqn of line : y = mx+ c

m = slope or gradient

c = y-intercept.

Lets take (1,6) = (x1,y1) and (2,3) = (x2,y2)

m \:  =  \frac{y1 - y2}{x1 - x2}  \\  =  \frac{6 - 3}{1 - 2}  \\ =  \frac{3}{ - 1}  \\  =  - 3

Substitute x = 1 and y = 6 into equation,

6 = ( - 3)(1) + c \\ 6 =  - 3 + c \\ c = 6 + 3 \\  = 9

Therefore substituting m and c value, equation of line is

y =  - 3x + 9

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Write a linear equation that passes through the two points (-6, -7) and (3, -4).
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linear equation that passes through the two points (-6, -7) and (3, -4) is y=\frac{1}{3}x-5

Step-by-step explanation:

We need to write the equation that passes through the two points (-6, -7) and (3, -4).

The equation can be written is point slope form.

The standard form of point slope equation is:

y=mx+b

where m is the slope and b is the y-intercept

Finding slope m:

Slope can be found by using formula:

slope = \frac{y_{2}-y_{1}}{x{2}-x_{1}} \\Where\,\, y_{2}=-4,y_{1}=-7,x{2}=3,x_{1}=-6\\slope =\frac{-4-(-7)}{3-(-6)}\\slope=\frac{-4+7}{3+6}\\slope=\frac{3}{9}\\slope=\frac{1}{3}

So, slope is \frac{1}{3}

Now finding y-intercept b

Putting slope \frac{1}{3} and point(-6,-7)

y=mx+b\\x=-6,y=-7,m=\frac{1}{3} \\-7=\frac{1}{3}(-6)+b\\-7=-2+b\\b=-7+2\\b=-5

So, value of b is -5

Putting values to find the equation:

y=mx+b\\m=\frac{1}{3} and b=-5\\y=\frac{1}{3}x-5

So, linear equation that passes through the two points (-6, -7) and (3, -4) is y=\frac{1}{3}x-5

Keywords: Linear Equation,

Learn more about Linear Equation at:

  • brainly.com/question/12954015
  • brainly.com/question/1979240
  • brainly.com/question/2601054

#learnwithBrainly

5 0
3 years ago
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