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makkiz [27]
3 years ago
10

It's not 3 so what's the volume?​

Mathematics
2 answers:
kkurt [141]3 years ago
7 0
The answer is 27. Volume of the cube
lidiya [134]3 years ago
7 0
I believe is is 729 b/c you have 6 sides to you times three 6 times
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Find the area of ΔABC. vertices are A(2, 1), B(3, 3), and C(1, 6)
Karolina [17]

Answer:

area = (1/2)|Ax(By-Cy) +Bx(Cy-Ay) +Cx(Ay-By)|

 = (1/2)|2(3-6) +3(6-1) +1(1-3)| = (1/2)|-6 +15 -2|

 area = 7/2

learn at brainly.com/question/17119045

7 0
2 years ago
A collector's model race car is scaled so that 1 inch on the model equals 6 1/4 feet on the actual car. If the model is 2/3 inch
Alchen [17]
The hight of the real car is 4 1/6 ft.
7 0
3 years ago
A survey of 600 randomly selected high school students determined that 290 play organized sports. what is the probability that a
blsea [12.9K]

Answer:

29/60

Step-by-step explanation:

probability of playing is 290/600 which when simplified is29/60

5 0
2 years ago
Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ
slega [8]
Using the law of cosine for Triangle KJL, we can write:

j^{2} = k^{2} + l^{2}-2(k)(l)cos(J)  \\  \\ 
2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\  \\ 
cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}

Using the values of k,j and l, we can write:

cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)}  \\  \\ 
cos(J)= 0.664 \\  \\ 
J= cos^{-1}(0.664) \\  \\ 
J=48.39

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer
8 0
3 years ago
Read 2 more answers
Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3​
maria [59]

Answer:

        a_1=4\\\\a_2=0\\\\a_3=3

Explanation:

The equation is:

      a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}

and

      a_4=-7, a_5=-36, a_6=-85

<u>1. Subsittute n = 6 into the equation:</u>

      a_6=3a_{5}-5a_{4}-4a_{3}

      Now subsititute the known values:

       -85=3(-36)-5(-7)-4a_{3}

      You can solve for a_3

      -85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3

<u />

<u>2. Substitute n = 5 into the equation:</u>

    a_5=3a_{4}-5a_{3}-4a_{2}

     Substitute the known values and solve for a_2

        -36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0

<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u>a_1<u />

       a_4=3a_{3}-5a_{2}-4a_{1}

        -7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4

7 0
3 years ago
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