The equation to be solved is: 3 [ 2 ^ (2t - 5) ] - 4 = 10
The steps are:
1) transpose - 4=> 3 [ 2^ (2t - 5) ] = 10 + 4
2) Combine like terms => 3 [2^ (2t - 5) ] = 14
3) Divide both terms by 3 => 2^ (2t - 5) = 14 / 3
4) Take logarithms of both sides => (2t - 5) log (2) = log (14/3)
5) Divide both sides by log (2) =>
log (14/3)
2t - 5 = -------------------
log (2)
6) transpose - 5+>
log (14/3)
2t = ------------------- + 5 = 2.22 + 5
log (2)
2t = 7.22
7) divide both sides by 2 => t = 7.22 / 2 = 3.61
5.3×10^5=53×10^4
53×10^4+3.8×10^4
=56.8×10^4
=5.68×10^5. Hope it help!
Answer:
1) b would be easier because it’s 1/2bh and since the base of 10 is easily divisible by 2 you don’t have to deal with fractions.
D=sqrt (x2-x1)^2+(y2-y1)^2
D=10
Step-by-step explanation:
The answer to the question is 3/7. add 1 and 2=3, it is 3/7
