Help would be appreciated.

A spherical object has a density rho. If it is compressed under high pressure to one third of its original diameter, its density

Ne4ueva [31]

Answer:

e. 27 rho.

Explanation:

The density of an object, assumed constant, is defined as the relationship between the mass and the volume.

If the object is compressed in such a way that the diameter is reduced to 1/3, this means, that the radius will be reduced in the same proportion.

Now, if the mass remains the same (the compression can't change it) , the volume (assumed to be a perfect sphere) will be reduced also:

V₀ = 4/3*π*r³

Vf= 4/3*π*(r/3)³ = 4/3*π*(r³/27) = V₀/27

As the volume is in in the denominator of the expression for density, this means that the new density will be equal to 27 times the original one:

ρ₀ = m/ V₀

ρ₁ = m/ V₁ = m/ (V₀/27) = 27* (m/V₀) = 27*ρ₀

8 0

4 years ago

Please help me do that.

Anika [276]

Answer:

a) 22.2 N

Explanation:

To find load effort. Identify load, efficiency and velocity ratio (VR)

Here given:

Load = 100 N

Efficiency = 75%

VR (number of pulleys) = 6

Effort :

$\rightarrow \sf \dfrac{MA}{VR} = \dfrac{Load \ \div \ efficiency }{VR} = \dfrac{100 \div 75 \% }{6} = 22.22 \ N$

3 0

3 years ago

Now try the following three examples: elements formula name barium phosphorus The element barium is an Alkaline Earth Metal, whi

saul85 [17]

Answer:

No element gains 4 electron in the case of transition element they bonds with covelent bonding whereby the electrons are shared around the last orbits

Explanation:

8 0

3 years ago

A small steel wire of diameter 1.0 mm is connected to an oscillator and is under a tension of 7.5 N. The frequency of the oscill

avanturin [10]

Answer:

a

The output power is $P= 0.764Watt$

b

The Amplitude would decrease by $\frac{1}{2}$

Explanation:

From the question we are told that

The diameter of the steel wire is = 1.0mm $= \frac{1}{1000} = 1.0*10^{-3}m$

The raduis of this steel wire is $r = \frac{1*10^{-3}}{2} = 0.5*10^{-3}m$

Now from the question we can deduce that the power output is equal to the power being transmitted by wave on the wire this is mathematically represented as

$P = \frac{1}{2} \mu w^2 A^2 v ----(1)$

Where $\mu$ is the mass per unit length of the wire

This is mathematically evaluated as

$\mu = a* \rho$

Where a is the area of the the wire = $\pi r^2 = (3.142 * 0.5*10^{-3})^2 =7.855*10^{-7}m^2$

$\rho$ is the density of steel with a generally value of $7850 kg/m^3$

So

$\mu = 7.855*10^{-7} *7850$

$= 6.162*10^{-3}kg/m$

$w$ is velocity of the wave

This is mathematically evaluated as

$w=2 \pi f$

substituting 60Hz for f

We have

$w = 2 *3.142 * 60$

$=377.04 \ rad/s$

$A$ is the amplitude with a given value of 0.50 cm $= \frac{0.50}{100} = 0.50 *10^{-2}m$

v is the linear velocity of the wave

This is mathematically evaluated as

$v = \sqrt{\frac{T}{\mu} }$

Where T is the tension with a given value of $7.5N$

$v = \sqrt{\frac{7.5}{6.162*10^{-3}} }$

$=34.89 m/s$

Substituting values into equation 1

$P = 6.162*10^{-3}* 377.04^2 * (0.5*10^{-2})^2 * 34.89$

$P= 0.764Watt$

Since the doubling of the frequency does not affect the amplitude and from equation one the output power is $\ \frac{1}{2}$ of the Amplitude, Then the Amplitude would decrease by $\frac{1}{2}$

4 0

3 years ago

A red light means to stop. If you are turning from a two-way road or onto a two-way road, then you are NOT allowed to turn

lyudmila [28]

A red light means to stop. If you are turning from a two-way road or onto a two-way road, then you are NOT allowed to reverse your car If you can't do it

Red is typically used to indicate danger or warning, and on traffic lights, it indicates a potential hazard ahead and, as a result, serves as a signal for drivers to stop. If the traffic light turns red while you are already at a junction, you must move swiftly to the opposite side to avoid a potential accident with oncoming traffic.
If the traffic light has turned red as you approach the junction and you are just entering it, you must stop. Unless there is a sign clearly telling you not to turn left at the red light, you may do so. Give way to people and cars coming from other directions when turning.

To learn more about Traffic lights please visit -
brainly.com/question/14871009
#SPJ1

7 0

2 years ago

Read 2 more answers