Answer:
12000 mph
Explanation:
Given that,
Distance read by the odometer = 120,000 miles
Duration of car, t = 10 years
We need to find the average speed of the car. Speed of an object is equal to the total distance covered divided by total time taken. So,

So, the average speed of the car is 12000 mph.
Ideal M.A. is 1 I.e, load =effort
Answer:
k = 6,547 N / m
Explanation:
This laboratory experiment is a simple harmonic motion experiment, where the angular velocity of the oscillation is
w = √ (k / m)
angular velocity and rel period are related
w = 2π / T
substitution
T = 2π √(m / K)
in Experimental measurements give us the following data
m (g) A (cm) t (s) T (s)
100 6.5 7.8 0.78
150 5.5 9.8 0.98
200 6.0 10.9 1.09
250 3.5 12.4 1.24
we look for the period that is the time it takes to give a series of oscillations, the results are in the last column
T = t / 10
To find the spring constant we linearize the equation
T² = (4π²/K) m
therefore we see that if we make a graph of T² against the mass, we obtain a line, whose slope is
m ’= 4π² / k
where m’ is the slope
k = 4π² / m'
the equation of the line of the attached graph is
T² = 0.00603 m + 0.0183
therefore the slope
m ’= 0.00603 s²/g
we calculate
k = 4 π² / 0.00603
k = 6547 g / s²
we reduce the mass to the SI system
k = 6547 g / s² (1kg / 1000 g)
k = 6,547 kg / s² =
k = 6,547 N / m
let's reduce the uniqueness
[N / m] = [(kg m / s²) m] = [kg / s²]
Answer:
technician A.
Explanation:
Commonly, air pressure rating of standard shop air compressor's is between the range of 100 psi and 150 psi. And over the years since, the plant pressure creep's up , the level of pressure increases from 100 psi to at max 150 psi but not more than that. Therefore, in the given question technician A is correct and technician B is incorrect.