Question

What is the value of the charge that experiences a force of 2.4 × 10–3 N in an electric field of 6.8 × 10–5 N/C?

Answer 1

From the dimensional analysis of the given units, it may be deduced that in order to determine the value of the charge, we have to divide the given force by the electric field such that
                               Charge = (2.4 x 10-3N) / (6.8 x 10-5 N/C)
                                Charge = 35.29 = 3.5 x 10^1 C
Thus, the answer is letter D. 

Answer 2

Answer:

D.3.5 × 101 C

Explanation:

The relationship between the force F experienced by a charge of magnitude q in an electric field of strength E is given by

$F=qE$

In this problem, we know the magnitude of the force ($F=2.4 \cdot 10^{-3}N$ and of the electric field ($E=6.8 \cdot 10^{-5}N/C$), so we can re-arrange the previous equation to find the magnitude of the charge, q:

$q=\frac{F}{E}=\frac{2.4 \cdot 10^{-3}N}{6.8 \cdot 10^{-5} N/C}=35.2 C=3.5 \cdot 10^1 C$